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`Since a dice has 6 sides the amount of sets for 2 dice is 6^2 or 36.`

Now we do the same for three dice 6^3 or 216.

Now I need to find how many combos out of 36 and 216 equal 8. I drew out every combo for the two dice since it was only 36 and came out with 5 different combos equaling 8. So 5/36. My teacher told us there is an easier way using the combo formula

C(n,r). She said since no set of 1's can equal 8 we only have 5 possible n's.

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`She showed us in class that to figure out for 2 dice we do:`

C(5,1)

My question is why does R = 1? Would it not be 2 since it's two dice?

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`And for 3 dice she showed`

C(6,1) + C(5,1) + C(4,1) + C(3,1) + C(2,1) + C(1,1)

I'm flat out not understanding the formula for the 3 dice. Can anyone make any sense of this for me? Thanks everyone. Forum rocks. I should be spending my time on these sites instead of bodybuilding forums lol.