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### Closed Form of ...[a][/n] = [3a][/n-1] - [2a][/n-2]

Posted: Thu Mar 10, 2011 4:17 pm
What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

Posted: Thu Mar 10, 2011 6:19 pm
What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]
What is the definition of the square brackets and the "slash" notation?

Thank you!

### Re: Closed Form of ...[a][/n] = [3a][/n-1] - [2a][/n-2]

Posted: Sat Mar 12, 2011 5:21 am
What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

$a_0 = 0, a_1 = 1 \text{ and } a_n = 3a_{n-1} - 2a_{n-2}$
$a_n=2^n-1$