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Closed Form of ...[a][/n] = [3a][/n-1] - [2a][/n-2]

Posted: Thu Mar 10, 2011 4:17 pm
by hbelle
What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

Posted: Thu Mar 10, 2011 6:19 pm
by stapel_eliz
What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]
What is the definition of the square brackets and the "slash" notation?

Thank you! :wink:

Re: Closed Form of ...[a][/n] = [3a][/n-1] - [2a][/n-2]

Posted: Sat Mar 12, 2011 5:21 am
by Martingale
What is the closed form for recursive equation [a][/0] = 0, [a][/1] = 1 and [a][/n] = [3a][/n-1] - [2a][/n-2]

is the closed form [a][/k+1] = [3a][/k+1-1] - [2a][/k+1-2] ???

if you had



then the closed form is just