^{2}-4]

y'= (1)(sqrt[x

^{2}-4])-(x)[(1/2)(x

^{2}-4)

^{-1/2}(2x)]/(x

^{2}-4)

= (sqrt[x

^{2}-4])-{(x)[(x)(x

^{2}-4)

^{-1/2}]}/(x

^{2}-4)

= (sqrt[x

^{2}-4])-[(x

^{2})(x

^{3}-4x)

^{-1/2}]/(x

^{2}-4)

= [(sqrt[x

^{2}-4])-x

^{2}]/[(x

^{2}-4)(sqrt[x

^{3}-4x])]

I also have to do the second derivative, but I would just like to make sure the first is right before continuing. Thanks.