How do I integrate [1/(2e^x - 3)]dx using substitution?

- Martingale
**Posts:**333**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
**Contact:**

How do I integrate [1/(2e^x - 3)]dx using substitution?

let

then

and

then the integral becomes

then use partial fractions

i dont know why i couldnt see that earlier

thanks!

thanks!