How do I integrate [1/(2e^x - 3)]dx using substitution?

- Martingale
**Posts:**335**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
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stellar wrote:How do I integrate [1/(2e^x - 3)]dx using substitution?

let

then

and

then the integral becomes

then use partial fractions

i dont know why i couldnt see that earlier

thanks!

thanks!