Helping students gain understanding and self-confidence in algebra.
yabo2k wrote:I'll do it step by step
Then do I need to find the antiderivative of the second part (2xe^3x)dx/3) because there are two fnc (2x/3) and (e^3x)
u= 2x/3 dv= (e^3x)dx
du= (2/3)dx v= (e^3x/3)
am I going in the right direction?