yabo2k wrote:find the antiderivative of x^2e^(3x)
yabo2k wrote:i get ((x^2e^3x)/3)-((2xe^3x)/9)-((2e^3x)/9)+C
yabo2k wrote:would it be e^(3x)/3?
yabo2k wrote:find the antiderivative of x^2e^(3x)
yabo2k wrote:I'll do it step by step
udv=(x^2)(e^3x/3)-(e^3x/3)(2xdx)
=(x^2e^3x)/3-(2xe^3x)dx/3)
Then do I need to find the antiderivative of the second part (2xe^3x)dx/3) because there are two fnc (2x/3) and (e^3x)
u= 2x/3 dv= (e^3x)dx
du= (2/3)dx v= (e^3x/3)
am I going in the right direction?