yabo2k wrote:find the antiderivative of (((ln(x))^2)/x dx. I am not sure how to go about solving this.
yabo2k wrote:so I get...(((ln(x))^2)+C
yabo2k wrote:so my u=ln(x) and my du= (1/x)dx
so using u and du i get......du(u)^2
so is my answer ((ln(x)^3)/3)+C