yabo2k wrote:( I don't know how to put in symbols but pi you know is equal to 3.14......)
as text, just write "pi", as you've done.
yabo2k wrote:A spherical snowball is placed in the sun. The sun melts the snowball so that its radius decreases .25 inch per hour. Find the rate of changee of the volume with respect to time at the instant the radius is 4 inches.
(dr/dt)=.25in r=in V=(4/3)(pi)r^3
Since the radius is de
creasing, rather than in
creasing, then dr/dt should be negative:. . . . .
...with the units being "inches per hour".
yabo2k wrote:Then is find the derevative of the Volume fnc
I got- (dv/dt)= 16in^3(pi) ( I don't know how to put in symbols but pi you know is equal to 3.14......)
You did the derivation correctly:. . . . .
You know that the radius, at the time in question, is r = 4, so you plugged this in, along with the value for dr/dt:. . . . .
The units on r^2 were obviously "inches squared", and the units on dr/dt were "inches per hour", so the "product" of r^2 and dr/dt has units "inches cubed per hour".
Note the major difference between your answer and the above: the "minus" sign. Since the ball is melting, shouldn't the volume be de
creasing, rather than (as you have it) in