Integrals: indefinite integral (1-cos(t/6))^6 sin(t/6) dt

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Integrals: indefinite integral (1-cos(t/6))^6 sin(t/6) dt

Postby doggy » Fri Apr 17, 2009 12:33 am

How do I evaluate the indefinite integral (1-cos(t/6))^6 sin(t/6)?

Would I use a u substitution of u= sin(t/6)?

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Martingale
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Re: Integrals

Postby Martingale » Fri Apr 17, 2009 12:40 am

doggy wrote:How do I evaluate the indefinite integral (1-cos(t/6))^6 sin(t/6)?

Would I use a u substitution of u= sin(t/6)?




how about

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Re: Integrals: indefinite integral (1-cos(t/6))^6 sin(t/6) dt

Postby doggy » Fri Apr 17, 2009 1:51 am

So then the answer would be (u^7/7)(6u) = ((1-cos(t/6))^7/7)(6(1-cos(t/6))

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Re: Integrals: indefinite integral (1-cos(t/6))^6 sin(t/6) dt

Postby Martingale » Fri Apr 17, 2009 2:01 am

doggy wrote:So then the answer would be (u^7/7)(6u) = ((1-cos(t/6))^7/7)(6(1-cos(t/6))



Martingale wrote:


how about





so






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