How do I evaluate the indefinite integral (1-cos(t/6))^6 sin(t/6)?
Would I use a u substitution of u= sin(t/6)?
doggy wrote:How do I evaluate the indefinite integral (1-cos(t/6))^6 sin(t/6)?
Would I use a u substitution of u= sin(t/6)?
doggy wrote:So then the answer would be (u^7/7)(6u) = ((1-cos(t/6))^7/7)(6(1-cos(t/6))
Martingale wrote:
how about