lim,h->0,{(2+h)^3 - 8}/h gives f' at some "a". Find f, a.

Limits, differentiation, related rates, integration, trig integrals, etc.
nona.m.nona
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lim,h->0,{(2+h)^3 - 8}/h gives f' at some "a". Find f, a.

Postby nona.m.nona » Fri Mar 06, 2009 4:12 pm

The limit, as h approaches 0, of {(2 + h)3 - 8} / h represents the derivative of some f(x) at some point a. Find f(x) and a.

Since 23 = 8, and since the formula for f'(x) is {f(x + h) - f(x)} / h as h goes to 0, is this just f(x) = x3 with a = 2?

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stapel_eliz
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Postby stapel_eliz » Fri Mar 06, 2009 5:26 pm

nona.m.nona wrote:...is this just f(x) = x3 with a = 2?

That's how I would read this. Good job! :D


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