^{3}- 8} / h represents the derivative of some f(x) at some point a. Find f(x) and a.

Since 2

^{3}= 8, and since the formula for f'(x) is {f(x + h) - f(x)} / h as h goes to 0, is this just f(x) = x

^{3}with a = 2?

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The limit, as h approaches 0, of {(2 + h)^{3} - 8} / h represents the derivative of some f(x) at some point a. Find f(x) and a.

Since 2^{3} = 8, and since the formula for f'(x) is {f(x + h) - f(x)} / h as h goes to 0, is this just f(x) = x^{3} with a = 2?

Since 2

- nona.m.nona
**Posts:**256**Joined:**Sun Dec 14, 2008 11:07 pm

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