nona.m.nona wrote:Find dy/dx for y = xx^x.
ln(y) = ln(xx^x) = xx ln(x)
But then what?
Give it another round of logarithmic differentiation! . . . . .. . . . .
Apply a log rule
to get:. . . . .. . . . .
Now differentiate:. . . . .
Simplify, and isolate the dy/dx. Make sure to substitute for "y" and "ln(y)" in the result.
Check my work!