Trig integral help  TOPIC_SOLVED

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Trig integral help

Postby Andromeda on Sat Jan 15, 2011 6:13 pm

I am having difficulty finding integral((tanx)^2 / (secx)^2)dx.

I tried converting everything in terms of sinx and cosx but that doesn't seem to help.
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Postby stapel_eliz on Sat Jan 15, 2011 8:40 pm

Andromeda wrote:I am having difficulty finding integral((tanx)^2 / (secx)^2)dx.

I tried converting everything in terms of sinx and cosx but that doesn't seem to help.

Once you've simplified and gotten an expression in just sine, you can use the double-angle formula (in reverse) for the cosine:

. . . . .

Then the integral is pretty straightforward. :wink:

Note: You will be using the double-angle formulas (in reverse) a lot in calculus, so make sure you're solid on them!
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Re:

Postby Andromeda on Sun Jan 16, 2011 8:50 pm

stapel_eliz wrote:
Andromeda wrote:I am having difficulty finding integral((tanx)^2 / (secx)^2)dx.

I tried converting everything in terms of sinx and cosx but that doesn't seem to help.

Once you've simplified and gotten an expression in just sine, you can use the double-angle formula (in reverse) for the cosine:

. . . . .

Then the integral is pretty straightforward. :wink:

Note: You will be using the double-angle formulas (in reverse) a lot in calculus, so make sure you're solid on them!


I'm still not sure I understand. Once I convert this into terms of sinx and cosx I have integral((sinx)^2 / (cosx)^4)dx. After that I should use the double angle forumual or half angle? The one you showed me is the half angle formual.
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Re: Trig integral help  TOPIC_SOLVED

Postby snowdrifter on Mon Jan 17, 2011 12:54 am

It simplifies like this:

(tanx)/(secx)
= ((sinx/cosx)/(1/(cosx))
=((sinx/cosx)*((cosx))
=sinx

It works the same way for the squared functions.
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