how to integrate x^2/(36-x^2)^(3/2): parts or substitution?

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chinex9a
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how to integrate x^2/(36-x^2)^(3/2): parts or substitution?

Postby chinex9a » Fri Sep 24, 2010 9:21 pm

How would you evaluate this integral ?

x^2/(36-x^2)^(3/2)

Parts or Substitution ?(I tried using substitution) Please explain.

nona.m.nona
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Re: x^2/(36-x^2)^(3/2)

Postby nona.m.nona » Sat Sep 25, 2010 12:12 am

I would suggest using substitution: x = 6*sin(u).

Wolfram: http://www.wolframalpha.com/input/?i=integrate+%28x^2%29%2F%2836-x^2%29^%283%2F2%29
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