trig: solving tanA=kcotB then cos(A+B)/cos(A-B)  TOPIC_SOLVED

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trig: solving tanA=kcotB then cos(A+B)/cos(A-B)

Postby yamini on Tue Aug 11, 2009 3:05 pm

can u please help me solving this problem
tanA=kcotB then cos(A+B)/cos(A-B)
1.1+k/1-k 2.1-k/1+k 3.k+1/k-1 4.k-1/k+1 :) :lol: :thumb: :confused:
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Postby stapel_eliz on Tue Aug 11, 2009 6:14 pm

A good start might be to notice that cotangent is the reciprocal of the tangent:

. . . . .

See if this helps with the application of angle-sum identities.... :wink:
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