rere wrote:If 90 degrees < 'theta' <180 degrees what is equaled to 5 cos 'theta' sec 'theta'?
I'm sorry, but I don't understand what this exercise is asking...? Are you supposed to find a range of value for the product of the 5, the cosine, and the secant? Or something else?
rere wrote:If cos 'theta' =1/2 the sin'theta' = WHAT?
Draw the right triangle. Label "adjacent" and "hypotenuse" sides with the values from the cosine ratio. Use the Pythagorean Theorem to find the value for the "opposite" side. Read off the value of the sine from the picture.