bazbeatz wrote:Solve the following equation for theta giving your answers in the interval from -180 to 180:
4sin'theta'cos'theta' + 1 = 2(sin'theta' + cos'theta')
You have the following:. . . . .
Squaring is a good idea, I think:. . . . .. . . . .. . . . .
But now use sin(2x) = 2sin(x)cos(x) to get:. . . . .. . . . .
Can you take it from there?