Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(x)-cot(  TOPIC_SOLVED

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Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(x)-cot(

Postby tampster on Sun Feb 26, 2012 6:14 am

Establish the following identity:

Please help, I'm not sure if I'm starting this correctly.

My attempt was(using "Left Hand Side"):
· Convert the tan and tan^2 to sin(x)/cos(x) and sin^2(x)/cos^2(x) respectively.

(cross multiply flipped denominator?)
Step 3. FOIL the sinx/cosx
Step 4. Fid a common denominator to get:

I don't see how to simplify any further to get it to match the "Right Hand Side". :confused:
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Postby stapel_eliz on Sun Feb 26, 2012 5:07 pm

tampster wrote:

(cross multiply flipped denominator?)

Since you did not have the two original terms combined using a common denominator, you cannot flip "the" fraction underneath. Try doing the conversion first, and see where this leads. :wink:

. . . . .

...and so forth.
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Re: Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(x)-

Postby tampster on Wed Feb 29, 2012 2:48 am

Well, I attempted the problem using your suggestion and I was able to reduce it to this, but do not see any further simplification possibilities:

The denominator could be changed to -cos(2x), but I don't see that helping.
The denominator could be factored to get (sinx-cosx)(sinx+cosx), but I don't see that helping either.

PLZ HELP my HW is due tomorrow :confused:
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Re: Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(x)-  TOPIC_SOLVED

Postby maggiemagnet on Wed Feb 29, 2012 2:09 pm

Try working on the other side. Change this to sines and cosines and do the common denominator. Then turn the dividing into multiplying, and compare what you get with what you already have on the left-hand side. You can then do the proof by showing the steps from where you are on the left-hand side, going backwards through the steps on the right-hand side, until you get to the starting place on the right-hand side.
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SOLVED Establishing an identity: tan(x)/(tan^2(x)-1)=1/(tan(

Postby tampster on Wed Feb 29, 2012 5:36 pm

Image (original left hand side equation all divided by tan)
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