There are two masses. Mass A is 0.2 kilograms, and is resting on a 30-degree slope. Mass B is 0.3 kilograms, and is hanging past the end of the slope from an inextensible string which passes over a smooth pulley.
Find the acceleration, a, of the particles when released from rest.
"T" is the tension in the string. Then
0.3g - T = 0.3a
T - 0.2g * sin(30 degrees) = 0.2a
But the answer doesn't match the back of the book. What did I do wrong?
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acceleration on particles, given A is on 30-degree slope 
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acceleration on particles, given A is on 30-degree slope
by theshadow on Sat Mar 07, 2009 4:36 pm
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by stapel_eliz on Sat Mar 07, 2009 11:54 pm
theshadow wrote:"T" is the tension in the string. Then...
T - 0.2g * sin(30 degrees) = 0.2a
Isn't the acceleration "a" on Mass A the tension on the string plus the amount of "pull" that gravity exerts as A slides down the slope...?
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stapel_eliz - Posts: 1706
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