trig identity problem: (sinx + tanx) / (1 + cosx) = tanx

[sully039]

(sinx+tanx)/(1+cosx)=tanx

So far I have,
L.S
(sinx+sinx/cosx)/(1+cosx)
[(sinxcosx+sinx)/(cosx)]/(1+cosx)
(sinxcosx+sinx)/(cosx) * 1/(1+cosx)
(sinxcosx+sinx)/(cosx+cos^2x)
...and now I'm stuck.

Could someone help me solve this and point out what I did wrong?
Thanks

[nona.m.nona]

[(sinxcosx+sinx)/(cosx)]/(1+cosx)
(sinxcosx+sinx)/(cosx) * 1/(1+cosx)

Factor the numerator "sin(x)cos(x) + sin(x)". Do the cancelation. Proceed from that point.