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korinkite wrote:...I must solve for theta2....
xsine(theta2) = L1sine(theta2 - theta1)
korinkite wrote:Here's what I received as an answer. Could you please let me know if I have it correctly? I got this for the first one:
theta2 = tan-1 ( (L1 sin(theta2) / (-x + L1 cos(theta1)) )
korinkite wrote:I simplified the second to be:
theta2 = theta1 + sin-1 ( (xsin(theta1)) / L2 )