The Purplemath Forums

Helping students gain understanding and self-confidence in algebra.

Skip to content

Hard problem with right triangles  TOPIC_SOLVED

Trigonometric ratios and functions, the unit circle, inverse trig functions, identities, trig graphs, etc.
Post a reply

  TOPIC_SOLVED

Postby stapel_eliz on Mon Nov 29, 2010 7:54 pm

dade488 wrote:So I get :
tanbeta=(m-s)/((s+m)/tanalpha)

...which simplifies as:

. . . . .

Now cross-multiply, expand, and solve for "m=". :wink:

dade488 wrote:If I keep going I get this:

tantheta= 5/(x+(36/x))...

Please show your work!
User avatar
stapel_eliz
 
Posts: 1797
Joined: Mon Dec 08, 2008 4:22 pm
Top

Sponsor

Sponsor
 
Top
Previous
Post a reply

Return to Trigonometry

Powered by phpBB © 2000, 2002, 2005, 2007 phpBB Group. Color scheme by ColorizeIt!