viewtopic.php?f=11&t=1497
If BC = x^2 - 18, CD =x + 2, C midpoint of BD, find x.
It means that BC is congruent(same length) as CD. I also need help with this problem
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If BC = x^2 - 18, CD =x + 2, C midpoint of BD, find x. 
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If BC = x^2 - 18, CD =x + 2, C midpoint of BD, find x.
by Mathwiz1 on Fri Sep 16, 2011 3:12 am
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Re: If BC = x^2 - 18, CD =x + 2, C midpoint of BD, find x. 
by little_dragon on Thu Sep 22, 2011 11:23 am
Mathwiz1 wrote:http://www.purplemath.com/learning/viewtopic.php?f=11&t=1497
If BC = x^2 - 18, CD =x + 2, C midpoint of BD, find x.
It means that BC is congruent(same length) as CD. I also need help with this problem
do like they said in the link: put them = & solve the eqn
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little_dragon - Posts: 152
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