cube has V = 512 cc; what is min. paper needed to cover?  TOPIC_SOLVED

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cube has V = 512 cc; what is min. paper needed to cover?

Postby clljhns on Sun Apr 10, 2011 1:32 pm

How do you solve the following problem?
A cube has a volume of 512 cubic centimeters.
SA e
V e
=
=
6× 2
3
If the cube is completely covered with wrapping paper, what is the minimum amount of paper
needed to cover all 6 faces?
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Postby stapel_eliz on Sun Apr 10, 2011 3:54 pm

clljhns wrote:How do you solve the following problem?
SA e
V e
=
=
6× 2
3

I don't know what you mean by the above, so I'm afraid I can't help here. :confused:

clljhns wrote:A cube has a volume of 512 cubic centimeters.If the cube is completely covered with wrapping paper, what is the minimum amount of paper needed to cover all 6 faces?

What is the formula for the volume V of a cube with side-length s? Plug the given volume value into this formula, and solve for the value of s.

What is the area of a square with side-length s = (the value you just found)?

The whole surface area is the area of this square (being one side or "face" of the cube), times the number of sides on the cube. :wink:
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Re: cube has V = 512 cc; what is min. paper needed to cover?

Postby clljhns on Sun Apr 10, 2011 4:56 pm

Sorry, I copied question and pasted. There is a box with a hint. It states that SA= 6 x e2 and V= e3, sorry I can't convert to exponents on this computer. So, given the V= 512 cc, how do I determine the minimum amount of paper needed to cover the box?
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Re: cube has V = 512 cc; what is min. paper needed to cover?

Postby clljhns on Sun Apr 10, 2011 5:13 pm

Thanks, I have it! :D
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