Consider the rational function f(x)= 3x^2 - 12 / x^2 - 3x + 2

A. Give the equation of the horizontal asymptote.

B. Give the equation(s) of any vertical asymptotes.

Thanks

- Tue May 11, 2010 2:42 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Give the equation of the horizontal and vertical asymtotes
- Replies:
**1** - Views:
**1050**

Consider the rational function f(x)= 3x^2 - 12 / x^2 - 3x + 2

A. Give the equation of the horizontal asymptote.

B. Give the equation(s) of any vertical asymptotes.

Thanks

A. Give the equation of the horizontal asymptote.

B. Give the equation(s) of any vertical asymptotes.

Thanks

- Mon May 10, 2010 11:43 pm
- Forum: Calculus
- Topic: Please help with a limit question
- Replies:
**2** - Views:
**1875**

Please determine the following limit if they exist. If the limit doe not exist put DNE.

lim 2x^3 / x^2 + 10x - 12

x->infinity.

Thanks.

lim 2x^3 / x^2 + 10x - 12

x->infinity.

Thanks.

- Mon May 10, 2010 12:03 am
- Forum: Calculus
- Topic: Determine if the following limits exist
- Replies:
**1** - Views:
**1591**

Please determine the following limits if they exist. If the limit does not exist put DNE. lim 2+6x-3x^2 / (2x+1)^2 x-> - infinity lim 4n-3 / 3n^2+2 n-> infinity I did lim 2+6x-3x^2 / (2x+1)^2 x-> - infinity (2+6x-3x²)/(4x²+4x+1) (2/x² + 6/x -3)/(4 + 4/x + 1/x²) as x-> - infinity. My answer is -3/4 l...

- Sat May 08, 2010 12:04 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Find the vertex, focus and directrix
- Replies:
**1** - Views:
**1251**

Sketech the graph of the equation y^2+4y+2x+10=0. Identify the vertex, the focus and the equation for the directrix. Use the completing the square to put the equation into standard form as your first step. This is what I did. y^2 + 4y = -2x-10 y^2 + 4y + 4 = -2x-6 (y+2)^2= -2(x+3) vertex: (-3, -2) F...

- Wed May 05, 2010 5:07 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Find the center, vertices, foci and eccentricity
- Replies:
**1** - Views:
**1234**

Find the center, vertices, foci and eccentricity of the ellipse given by the following problem. x^2 / 11 + y^2 / 36 =1. Did I do it right? Thanks My answers. Center: (0,0) Vertices: (0,6) and (0,-6) Foci: (0,5) and (0, -5) eccentricity= 5/6 a^2=36 a=6 b^2=11 b=square root of 11 = 3.32 a^2=b^2+c^2 36...

- Wed May 05, 2010 3:23 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Find the limit by direct substitution.
- Replies:
**1** - Views:
**1333**

Find the limit by direct substitution. A. lim x-> 5 square root cubed of x^2 -2x - 23. I replaced all of the x's with 5 and got -2. B. lim x-> -2 (4x^2 - 7x) / (6x + 10). I replaced all of the x's with -2 and got -15. Here's a link to the problem. It's 3A and 3B. Thanks. http://pic20.picturetrail.co...