- Wed Sep 28, 2011 2:55 pm
- Forum: Calculus
- Topic: Calculus 2 (limits): limit as x -> 0+ of 1/x + lnx
- Replies:
**5** - Views:
**2389**

Thanks for the explanation. I have done lots of derivatives as I am now in second semester calculus. But I need to know how to evaluate this limit ALGEBRIACALLY and WITHOUT GRAPHING. Would you know how to work this problem using algebra? Thanks.

- Tue Sep 27, 2011 2:41 pm
- Forum: Calculus
- Topic: Calculus 2 (limits): limit as x -> 0+ of 1/x + lnx
- Replies:
**5** - Views:
**2389**

It is the limit of (1/x) + ln(x). Thanks! Please help. I really appreciated!!

- Mon Sep 26, 2011 5:53 pm
- Forum: Calculus
- Topic: Calculus 2 (limits): limit as x -> 0+ of 1/x + lnx
- Replies:
**5** - Views:
**2389**

Hello, I need help with this limit. The limit as x approaches zero from the right of 1/x + lnx. The answer is positive infinity but I am not sure how to work the problem. I tried to combine the fraction and other algebra tricks but I get indeterimante forms. I tried L'Hopitals rule as well but could...

- Tue Nov 30, 2010 3:12 pm
- Forum: Geometry
- Topic: How to find the area of a cross section of a cube.
- Replies:
**1** - Views:
**2713**

I wish I could draw the problem but I cant's so I will try to explain it. I have a cube. The lenghts of the sides of the cube is 8. Inside the center of this cube there is a cross section in the shape of a sqaure. The four corners of this square are the midpoints of the sides of the cube. I have to ...

- Mon Oct 18, 2010 4:18 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Need help verifying an answer about piecewise functions.
- Replies:
**1** - Views:
**1786**

Here is the problem: Find the domain and range of this piecewise defined function; f(x)= -2x^2 with restriction x greater than or equal to -2 and less than 1 -0.5 with restriction x=1 x with restriction x greater than 1 After graphing the piecewise functions, I determined that the domain = [-2, posi...

- Sun Sep 26, 2010 4:31 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Can someone please help me solve this polynomial equation?
- Replies:
**2** - Views:
**1370**

I have x^6 - 1=0 After the rational roots test, I have the factors of (x+1)(x-1). So, after doing the synthetic division with these factors I am left with x^4 + x^2 + 1. Now I am stuck. This equation does not factor, and it is not a quadratic. How do I move forward from here? The roots by the way ar...

- Wed Sep 22, 2010 12:38 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Can someone help me simplify this radical expression?
- Replies:
**2** - Views:
**1824**

Thank you for your help! I now understand on how to get the correct answer.

- Tue Sep 21, 2010 7:20 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Can someone help me simplify this radical expression?
- Replies:
**2** - Views:
**1824**

I have the cube root of 15 divided by the cube root of 10. First I simplified the fraction to the cube root of 3 divided by the cube root of 2. Then if I rationalize the denominator I am left with the cube root of 6 divided by the cube root of 4. The answer seems to be the cube root of 12 divided by...

- Thu Jul 29, 2010 2:56 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: techniques for finding an expression for geometric seqeunces
- Replies:
**1** - Views:
**1066**

I know that there are certain techniques and steps on finding expressions for linear and quadratic sequences. But can someone give me a technique or set of steps that I can use to figure out expressions for geometric sequences? For example, I have the geometric sequence 4,8,16,32,64.... The common r...

- Tue Jul 06, 2010 2:13 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: How do I find the nth term of this sequence?
- Replies:
**2** - Views:
**1868**

I have the sequence 2,8,26,80,242

So b sub n = 6,18,54,162

b sub 1 = 6

r = 3

using the geometric formula I have 6 times 3^(n-1).

Now I am stuck? What are the next steps? Please help!

So b sub n = 6,18,54,162

b sub 1 = 6

r = 3

using the geometric formula I have 6 times 3^(n-1).

Now I am stuck? What are the next steps? Please help!