The Purplemath Forums

twice as many field goals as touchdowns: x = # of touchdowns 2x = # of fieldgoals a touchdown is worth 7 (I thought it was 6, but anyway) a field goal is worth 3 7(# of touchdowns) + 3(# of field goals) = 26 7x + 3(2x) = 26 7x + 6x = 26 {multiply 3(2x)} 13x = 26 {combine like terms) x = 2 touchdowns...

Go back to:
QN = N - S

Add S to both sides and subtract QN from both sides

S = N - QN
S = N(1 - Q) {factor an N out}
N = S/1-Q {divide both sides by (1- Q)