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[SPLIT] follow-up on 'cost' equation for lemonade stand  TOPIC_SOLVED

In reference to this thread : Suppose you have a lemonade stand, and when you charge $1 per cup of lemonade you sell 50 cups. But when you raise your price to $2 you only sell 25 cups. Write an equation for the number of cups you sell as a function of the price you charge. Denote "C" for n...
by ironape
on Wed Oct 07, 2009 4:49 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] follow-up on 'cost' equation for lemonade stand
Replies: 6
Views: 1531

Re: would this be right?  TOPIC_SOLVED

Would you solve this using the function f(p)=mc+b?

So are the points (1,25) and (2,50)? (p,c)?

It looks like a linear line and the slope would be rise 25, run 1 so m=25?

Am I on the right track?
by ironape
on Thu Oct 08, 2009 1:40 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] follow-up on 'cost' equation for lemonade stand
Replies: 6
Views: 1531

Re: would this be right?  TOPIC_SOLVED

oops i had that backwards... would the points be (1,50),(2,25)

and is the rest correct to get me going in the right direction?
by ironape
on Thu Oct 08, 2009 2:34 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] follow-up on 'cost' equation for lemonade stand
Replies: 6
Views: 1531

Re: would this be right?  TOPIC_SOLVED

yep your right. m=(y2-y1)/(x2-x1) m= (25-50)/(2-1) m= -25/1 m=-25 Graphing it out and extrapolating shows that this is a inverse graph and that the y-intersection would be 75. This is the correct answer. f(x)=-25m+75 (1,50) f(x)=-25m+75 f(x)=-25(1)+75 f(x)=-25+75 f(x)=50 Thanks for all the help ever...
by ironape
on Thu Oct 08, 2009 5:29 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] follow-up on 'cost' equation for lemonade stand
Replies: 6
Views: 1531

Solve linear equations with 2 unknowns  TOPIC_SOLVED

Im just not seeing what im doing wrong to solve this. Can anyone take a look and let me know where I am going wrong with it? 4x + 1y = 16 -3(4x + 1y) = -3(16) -12x + -3y = -48 2x + 3y = -24 -10x + 0y = -24 -10x = -24 -10/-10 = -24/-10 x = -2.4 4(-2.4) + 1y = 16 -9.6 + 1y = 16 (-9.6+9.6) + 1y = (16 +...
by ironape
on Wed Oct 14, 2009 5:45 pm
 
Forum: Beginning Algebra
Topic: Solve linear equations with 2 unknowns
Replies: 8
Views: 2944

Re: Solve linear equations with 2 unknowns  TOPIC_SOLVED

4x + 1y = 16

2X + 3Y = 24
by ironape
on Mon Oct 19, 2009 1:56 pm
 
Forum: Beginning Algebra
Topic: Solve linear equations with 2 unknowns
Replies: 8
Views: 2944

Re: Solve linear equations with 2 unknowns  TOPIC_SOLVED

whats the answer so i can try and figure out what ive done wrong. The way ive worked the problem has been the same for 10 other problems and they all came out right. I just dont know what im missing with this one.
by ironape
on Thu Oct 22, 2009 2:01 pm
 
Forum: Beginning Algebra
Topic: Solve linear equations with 2 unknowns
Replies: 8
Views: 2944

Re: Solve linear equations with 2 unknowns  TOPIC_SOLVED

Problem: 4x+y=16 2x+3y=24 im going to solve for x since i can easily remove y in the first equation by multiplying by -3 4x + 1y = 16 -3(4x + 1y) = -3(16) -12x + -3y = -48 I get the above result which i will subtract the second equation from -12x + -3y = -48 2x + 3y = 24 -10x + 0y = -24 -10x = -24 -...
by ironape
on Thu Oct 22, 2009 5:16 pm
 
Forum: Beginning Algebra
Topic: Solve linear equations with 2 unknowns
Replies: 8
Views: 2944

Re: Solve linear equations with 2 unknowns  TOPIC_SOLVED

The problem is equation B is: 2x+3y = 24 <positive 24> not 2x + 3y = -24 It doesnt matter because I found where I messed up. I have to be careful when figuring if an answer is negative or positive. I made 2 mistakes which skewed the answers. Inputting the below answers will check out. x=2.4 y=9.6 Th...
by ironape
on Thu Oct 22, 2009 7:10 pm
 
Forum: Beginning Algebra
Topic: Solve linear equations with 2 unknowns
Replies: 8
Views: 2944

Correct equations?  TOPIC_SOLVED

Suppose Bob owns 2,000 shares of Company X and 10,000 shares of Company Y. The total value of Bob's holdings of these two companies is $340,000. Suppose Frank owns 8,000 shares of Company X and 6,000 shares of Company Y. The total value of Franks holdings of these two companies is $340,000. Write eq...
by ironape
on Thu Oct 22, 2009 8:48 pm
 
Forum: Beginning Algebra
Topic: Correct equations?
Replies: 1
Views: 833
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