- Wed Jan 27, 2010 6:03 pm
- Forum: Statistics
- Topic: Frequency distribution chart
- Replies:
**1** - Views:
**3343**

Can someone point me in the right direction to get the chart made? The materials i was given dont make much sense to me. You are the production manager for an operation that produces circuit boards. Each board is tested at the end of the manufacturing process. Rejected boards are discarded and have ...

- Mon Nov 09, 2009 9:31 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Log question: 6^3 = 216; answer: log_6(216) = 3
- Replies:
**1** - Views:
**4260**

Problem: 6^{3} = 216

Answer: log_{6}(216) = 3

My question is... does it have to be log_{6}(216) = 3 or can it be 3 = log_{6}(216). Does it matter if the = 3 / 3 = comes first or last?

I dont want to get it wrong because it was formatted backwards. Does that make sense?

Answer: log

My question is... does it have to be log

I dont want to get it wrong because it was formatted backwards. Does that make sense?

- Fri Oct 30, 2009 3:46 pm
- Forum: Intermediate Algebra
- Topic: distance between points
- Replies:
**3** - Views:
**1007**

I couldnt show the square root. Thanks for the tip.

so exponents then addition.

so exponents then addition.

- Fri Oct 30, 2009 1:33 pm
- Forum: Intermediate Algebra
- Topic: distance between points
- Replies:
**3** - Views:
**1007**

This really isnt a question on how to do it but more of a rules thing. Do I add the squared numbers together before before multiplication or do I sqaure them individually then add? See below for the examples. c. The distance between the points (1,4) and (19,6). d = (x2 - x1)² + (y2-y1)² d= (19 - 1)²...

- Thu Oct 29, 2009 5:32 pm
- Forum: Intermediate Algebra
- Topic: point on the x-axis
- Replies:
**1** - Views:
**728**

The point on the x-axis that is equidistant (equal distance) from (12,6) and (8,2).

Im not sure what i need to do to solve this. Do i need to run the distance formula? midpoint formula?

Can someone point me in the right direction as I cant find a example of how to solve this anywhere.

Thanks

Im not sure what i need to do to solve this. Do i need to run the distance formula? midpoint formula?

Can someone point me in the right direction as I cant find a example of how to solve this anywhere.

Thanks

- Thu Oct 29, 2009 3:51 pm
- Forum: Beginning Algebra
- Topic: perpendicular through coords
- Replies:
**1** - Views:
**998**

My math skills are really rusty so if i could get someone to check this answer I would appreaciate it. A line that passes through (1, 1) and is perpendicular to the line 3x+4Y=12. 3x + 4y = 12 <----convert to y = mx + b 4y = -3x +12 (4/4)y = (-3/4)x + (12/4) y = -3/4 + 3 Now we know that m1 = -3/4 s...

- Thu Oct 29, 2009 1:00 pm
- Forum: Beginning Algebra
- Topic: Find the equation
- Replies:
**5** - Views:
**1529**

A line that passes though the points (2,4) and (8,16)

would you solve this the same way?

find the slope with m=(y2-y1)/(x2-x1)

then use (2,4) as (x,y)

solve for b?

would you solve this the same way?

find the slope with m=(y2-y1)/(x2-x1)

then use (2,4) as (x,y)

solve for b?

- Wed Oct 28, 2009 8:54 pm
- Forum: Beginning Algebra
- Topic: Find the equation
- Replies:
**5** - Views:
**1529**

OK so I gather they are both wrong.

is this how I would find the equation?

A line that passes through (6,2) and has a slope of 2.

y = mx + b

2 = 2(6) + b <---substitue x=6, y=2

2 = 12 + b

(2-12) = (12-12) + b <---subtract

-10 = b

2 = 2(6) - 10

2 = 12 - 10

2 = 2

answer: y = 2x -10???

is this how I would find the equation?

A line that passes through (6,2) and has a slope of 2.

y = mx + b

2 = 2(6) + b <---substitue x=6, y=2

2 = 12 + b

(2-12) = (12-12) + b <---subtract

-10 = b

2 = 2(6) - 10

2 = 12 - 10

2 = 2

answer: y = 2x -10???

- Wed Oct 28, 2009 8:14 pm
- Forum: Beginning Algebra
- Topic: Find the equation
- Replies:
**5** - Views:
**1529**

Find the equation for each of the following items below: 1. A line that passes through (6,2) and has a slope of 2. y = mx +b Slope = 2 so y = 2x + b y = 2 from (6,2) 2 = 2x + b Need to find the y intercept so I substituted 0 for x and got: 2 = 2(0) + b 2 = b answer: y = 2x + 2 2. A line that passes...

- Mon Oct 26, 2009 2:08 pm
- Forum: Beginning Algebra
- Topic: Solving an equation with 3 undefined variables
- Replies:
**2** - Views:
**1171**

Thank you very much