- Sun Nov 22, 2009 3:21 am
- Forum: Intermediate Algebra
- Topic: Linear-Quadratic Systems - Comparison Method
- Replies:
**2** - Views:
**1005**

Basically when you relate quadratics to linears you are trying to find for what values the line will intersect the parabola, might be just once, twice or never. So when you equate the two equations you are assuming the y is the same for both. Here is a youtube vid that shows the concept, except the ...

- Sun Nov 22, 2009 12:00 am
- Forum: Intermediate Algebra
- Topic: Linear-Quadratic Systems - Comparison Method
- Replies:
**2** - Views:
**1005**

So this is a pretty simple concept. I find it fairly easy to go through all the steps of the process. However, in the exercises that I've been doing I find myself wondering if it is convenient to stick to the exact values or just round it off to a decimal in order to make it easier for when I need t...

- Tue Nov 17, 2009 10:46 pm
- Forum: Intermediate Algebra
- Topic: Transformations of y = x^2
- Replies:
**2** - Views:
**1174**

Thank you so much!!! you always help me figure these things out and I'm grateful for that. Though I'm going to mention that I asked my teacher about this and he said to work it out by expanding it which would leave me with ax^2 + bx + c, but it still isn't a convinient way to look at it because I wo...

- Tue Nov 17, 2009 12:27 am
- Forum: Intermediate Algebra
- Topic: Transformations of y = x^2
- Replies:
**2** - Views:
**1174**

Can someone help me get this clear?

For the function y = (3x + 7)^2

A suitable description of the transformation would be that y = x^2 has been horizontally translated 2.333 units to the left and it has also been horizontally compressed by a factor of 1/3.

is this correct?

For the function y = (3x + 7)^2

A suitable description of the transformation would be that y = x^2 has been horizontally translated 2.333 units to the left and it has also been horizontally compressed by a factor of 1/3.

is this correct?

- Mon Nov 02, 2009 11:09 pm
- Forum: Intermediate Algebra
- Topic: is it possible to have a negative fraction as a restriction?
- Replies:
**3** - Views:
**1191**

Thanks

I was actually referring to a case in where we need to set restrictions on the denominator, but I've never seen a negative fraction as a restriction so that's why I'm asking.

I was actually referring to a case in where we need to set restrictions on the denominator, but I've never seen a negative fraction as a restriction so that's why I'm asking.

- Mon Nov 02, 2009 8:44 pm
- Forum: Intermediate Algebra
- Topic: is it possible to have a negative fraction as a restriction?
- Replies:
**3** - Views:
**1191**

When simplyfing rational expressions, after factoring:

Say I have (3x - 8)

can I state that x cannot be -8/3?

Say I have (3x - 8)

can I state that x cannot be -8/3?

- Tue Oct 27, 2009 10:08 pm
- Forum: Intermediate Algebra
- Topic: finding the inverse of this function? f (x) = 2/3 (x) - 4
- Replies:
**3** - Views:
**1516**

if my functions is f (x) = 2/3 (x) - 4 Is the above any of the following? . . . . . \mbox{a) }\, f(x)\, =\, \frac{2}{3x\, -\, 4} . . . . . \mbox{b) }\, f(x)\, =\, \frac{2}{3x}\, -\, 4 . . . . . \mbox{c) }\, f(x)\, =\, \frac{2}{3} x\, -\, 4 Or something else? I ap...

- Tue Oct 27, 2009 8:55 pm
- Forum: Intermediate Algebra
- Topic: finding the inverse of this function? f (x) = 2/3 (x) - 4
- Replies:
**3** - Views:
**1516**

if my functions is f (x) = 2/3 (x) - 4 can't my inverse be: f^i (x) = x + 4 / (2/3) I mean all I'm doing is just reversing the operations but for example in my book for the following functions, they have a different inverse? g (x) = 5/2 (x) - 4 and the answer at the back is: g^i = 2x + 8 / (5) can s...

- Sat Oct 17, 2009 7:36 pm
- Forum: Discrete Math
- Topic: Can someone help me figure out a recursive formula for this?
- Replies:
**2** - Views:
**2673**

THANK YOU SO MUCHH!! I get it all now, thnx a lot, for the last two i was able to find formulas that work, just like the one you hinted me to see, it works both ways, but i'll use yours cause it's simpler, and the first one, GOD I swear I couldn't see the pattern in it :roll: But Thanks Again, I'm v...

- Thu Oct 15, 2009 10:51 pm
- Forum: Discrete Math
- Topic: Can someone help me figure out a recursive formula for this?
- Replies:
**2** - Views:
**2673**

I GIVE UP, seriouosly i've tried so many ways to figure this out but i just can't seem to see the pattern :oops: :oops: :oops: Find the next two numbers in each sequence. A) -1, 1 , 3 , 7 , 15 , ______ , _______ B) 3, 1, 2 , -1 , 3 , -4 , ______, _______ C) 16, 24, 36 , 54 , 81, ______, ______ just ...