The Purplemath Forums

can someone help me figure out a pattern for the above sequence? and i guess i would also need help creating the general term, but any help will be greatly appreciated!

Thanks in advance!

Thanks a lot!! I just needed to open my mind a bit more to other possibilities. I figured it out and it would like like this 2, 3, 7, 16, 32, 57… Exercise number 1 states to find the next to numbers, and exercise two asks to provide a formula for the nth term of this sequence. Thanks again! Now do y...

is the following expression correct? i mean it's logical to me but i'm not sure if you can do this:

tn = tn-1 + 1 + n

Another way of doing it I think could be by looking into quadratics, but i don't want it to be very complicated.

find an expression for the general term of these sequences?

C) 144, 121, 100, 81, 64, 49…

F) 2, 3, 7, 16, 32, 57…

I've been trying hard, but i can't seem to find a formula which would work for the nth term.

According to yahoo answer, these are possible general terms

ist series numbering from 1^2..is
Tn=T1+(n+1)(n-1)..or Tn=(13-n)^2..goin down the way..
2nd series is
Tn=T1+[(2n-1)(n-1)n]/6..where T1=first term

I GIVE UP, seriouosly i've tried so many ways to figure this out but i just can't seem to see the pattern :oops: :oops: :oops: Find the next two numbers in each sequence. A) -1, 1 , 3 , 7 , 15 , ______ , _______ B) 3, 1, 2 , -1 , 3 , -4 , ______, _______ C) 16, 24, 36 , 54 , 81, ______, ______ just ...

THANK YOU SO MUCHH!! I get it all now, thnx a lot, for the last two i was able to find formulas that work, just like the one you hinted me to see, it works both ways, but i'll use yours cause it's simpler, and the first one, GOD I swear I couldn't see the pattern in it :roll: But Thanks Again, I'm v...

if my functions is f (x) = 2/3 (x) - 4 can't my inverse be: f^i (x) = x + 4 / (2/3) I mean all I'm doing is just reversing the operations but for example in my book for the following functions, they have a different inverse? g (x) = 5/2 (x) - 4 and the answer at the back is: g^i = 2x + 8 / (5) can s...

if my functions is f (x) = 2/3 (x) - 4 Is the above any of the following? . . . . . \mbox{a) }\, f(x)\, =\, \frac{2}{3x\, -\, 4} . . . . . \mbox{b) }\, f(x)\, =\, \frac{2}{3x}\, -\, 4 . . . . . \mbox{c) }\, f(x)\, =\, \frac{2}{3} x\, -\, 4 Or something else? I ap...

When simplyfing rational expressions, after factoring:

Say I have (3x - 8)

can I state that x cannot be -8/3?