- Tue Mar 02, 2010 6:00 pm
- Forum: Intermediate Algebra
- Topic: Finding Distance Between Points
- Replies:
**3** - Views:
**1573**

Hi everyone, I have the formula http://www.purplemath.com/modules/xyplane/dist07b.gif (Yes, I got that from a Purplemath Leeson*). To find the distance I am supposed to plug my coordinates into the formula, right? But what about when the coordinates are this (or something like this): (6,5 \sqrt{2} )...

- Fri Feb 05, 2010 2:45 pm
- Forum: Arithmetic
- Topic: Negative Exponents
- Replies:
**3** - Views:
**3919**

That was the expression, would that simplify to ?If the expression was , then you have . How does that simplify?

- Thu Feb 04, 2010 4:25 pm
- Forum: Arithmetic
- Topic: Negative Exponents
- Replies:
**3** - Views:
**3919**

Ok, maybe I misread my book, but this is from my book: For any number "a" (except zero), a 0 = 1. Now I have a homework problem: Simplify the expression: mn 0 So, I put in for my answer 1, but when it was graded the teacher said that that was the wrong answer. How could it be wrong if any number the...

- Thu Feb 04, 2010 3:23 pm
- Forum: Intermediate Algebra
- Topic: Factoring Polynomials
- Replies:
**3** - Views:
**2851**

The hard part is in finding the numbers to use for splitting the middle (linear) term. You can see more examples here . Start with the "easy" case, as understanding that factorization can be very helpful for the "hard" case (where the leading coefficient is something other than 1). :wink: But what ...

- Wed Feb 03, 2010 2:50 pm
- Forum: Intermediate Algebra
- Topic: Factoring Polynomials
- Replies:
**3** - Views:
**2851**

Hi everyone, where can I find help on how to factor polynomials? The examples in my math book don't really explain it enough for me to understand. Find the factors of ac + ad + bc + bd. Group the four terms into two pairs, then separate the GCF from each pair: ac + ad + bc + bd =(ac + ad) + (bc + bd...

- Mon Oct 26, 2009 4:16 pm
- Forum: Beginning Algebra
- Topic: Slope-intercept form of an equation
- Replies:
**1** - Views:
**1258**

Hi everyone, I know that the "slope-intercept form" of an equation is y=mx+b. M as the slope, and B as the y-intercept, but how would I convert this to the general form of a linear equation, "ax+bx+c=0" ? Can anyone help?

- Thu Oct 15, 2009 3:21 pm
- Forum: Pre-Algebra
- Topic: Don't understand this equation
- Replies:
**1** - Views:
**1980**

There is an equation in my book: Solve for y in the equation " ". Um... how would I solve that?

- Tue Oct 13, 2009 2:58 pm
- Forum: Geometry
- Topic: Finding slope between two points
- Replies:
**1** - Views:
**3449**

Does anyone know how to find the slope between two points without graph paper, such as: (0,-1) and the point (3,5). In one part of my book it says subtract the ordinates from each other and the abiscas from each other (i.e. : -1-5=-6 and 0-3=-3, subtracting the second point, from the first point.) B...

- Mon Oct 12, 2009 3:11 pm
- Forum: Beginning Algebra
- Topic: Direct Variations definition
- Replies:
**1** - Views:
**1052**

Hi, I'm having trouble with Direct Variations. Can anyone help me?

- Fri Oct 02, 2009 2:02 pm
- Forum: Geometry
- Topic: Functions: having trouble with definition in my book
- Replies:
**5** - Views:
**4152**

Thanks!Yes. The x-value is the "independent" variable: you, independently, choose the value of x. The y-value is the "dependent" variable: it depends on what you picked for x.