Search found 25 matches

Go to advanced search

by iceking
Tue Mar 02, 2010 6:00 pm
Forum: Intermediate Algebra
Topic: Finding Distance Between Points
Replies: 3
Views: 1215

Finding Distance Between Points

Hi everyone, I have the formula http://www.purplemath.com/modules/xyplane/dist07b.gif (Yes, I got that from a Purplemath Leeson*). To find the distance I am supposed to plug my coordinates into the formula, right? But what about when the coordinates are this (or something like this): (6,5 \sqrt{2} )...
by iceking
Fri Feb 05, 2010 2:45 pm
Forum: Arithmetic
Topic: Negative Exponents
Replies: 3
Views: 2290

Re: Negative Exponents

stapel_eliz wrote:If the expression was , then you have . How does that simplify?



That was the expression, would that simplify to ?
by iceking
Thu Feb 04, 2010 4:25 pm
Forum: Arithmetic
Topic: Negative Exponents
Replies: 3
Views: 2290

Negative Exponents

Ok, maybe I misread my book, but this is from my book: For any number "a" (except zero), a 0 = 1. Now I have a homework problem: Simplify the expression: mn 0 So, I put in for my answer 1, but when it was graded the teacher said that that was the wrong answer. How could it be wrong...
by iceking
Thu Feb 04, 2010 3:23 pm
Forum: Intermediate Algebra
Topic: Factoring Polynomials
Replies: 3
Views: 1921

Re: Factoring Polynomials

The hard part is in finding the numbers to use for splitting the middle (linear) term. You can see more examples here . Start with the "easy" case, as understanding that factorization can be very helpful for the "hard" case (where the leading coefficient is something other than ...
by iceking
Wed Feb 03, 2010 2:50 pm
Forum: Intermediate Algebra
Topic: Factoring Polynomials
Replies: 3
Views: 1921

Factoring Polynomials

Hi everyone, where can I find help on how to factor polynomials? The examples in my math book don't really explain it enough for me to understand. Find the factors of ac + ad + bc + bd. Group the four terms into two pairs, then separate the GCF from each pair: ac + ad + bc + bd =(ac + ad) + (bc + bd...
by iceking
Mon Oct 26, 2009 4:16 pm
Forum: Beginning Algebra
Topic: Slope-intercept form of an equation
Replies: 1
Views: 952

Slope-intercept form of an equation

Hi everyone, I know that the "slope-intercept form" of an equation is y=mx+b. M as the slope, and B as the y-intercept, but how would I convert this to the general form of a linear equation, "ax+bx+c=0" ? Can anyone help?
by iceking
Thu Oct 15, 2009 3:21 pm
Forum: Pre-Algebra
Topic: Don't understand this equation
Replies: 1
Views: 1482

Don't understand this equation

There is an equation in my book: Solve for y in the equation " ". Um... how would I solve that? :confused:
by iceking
Tue Oct 13, 2009 2:58 pm
Forum: Geometry
Topic: Finding slope between two points
Replies: 1
Views: 2633

Finding slope between two points

Does anyone know how to find the slope between two points without graph paper, such as: (0,-1) and the point (3,5). In one part of my book it says subtract the ordinates from each other and the abiscas from each other (i.e. : -1-5=-6 and 0-3=-3, subtracting the second point, from the first point.) B...
by iceking
Mon Oct 12, 2009 3:11 pm
Forum: Beginning Algebra
Topic: Direct Variations definition
Replies: 1
Views: 791

Direct Variations definition

Hi, I'm having trouble with Direct Variations. Can anyone help me?
by iceking
Fri Oct 02, 2009 2:02 pm
Forum: Geometry
Topic: Functions: having trouble with definition in my book
Replies: 5
Views: 3291

Re:

stapel_eliz wrote:Yes. The x-value is the "independent" variable: you, independently, choose the value of x. The y-value is the "dependent" variable: it depends on what you picked for x.


Thanks! :D

Go to advanced search