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solve the equation 4 cot^2 x + 12cosecx + 1 = 0 for 0<x<360  TOPIC_SOLVED

hi i was wondering if anyone could help me with this question

solve the equation 4 cot^2 x+12cosecx+1=0 giving all values of x to the nearest degree in the interval 0<x<360(should be equal to signs as well but comp doesnt do them)

thanks for any help much appreciated
by mannilea
on Wed Sep 09, 2009 2:35 pm
 
Forum: Trigonometry
Topic: solve the equation 4 cot^2 x + 12cosecx + 1 = 0 for 0<x<360
Replies: 4
Views: 2351

solving the equation 3 sec^2 pheta +7= 11 tan pheta  TOPIC_SOLVED

hi wasnt sure whether the two questions should be together or seperate sorry if they were meant to got together solve the equation 3 sec^2 pheta +7= 11 tan pheta giving all values of x to 3sf in the interval 0<pheta<2pi sorry for the bad setting out dont no how to get pheta and pi signs thanks for a...
by mannilea
on Wed Sep 09, 2009 2:36 pm
 
Forum: Trigonometry
Topic: solving the equation 3 sec^2 pheta +7= 11 tan pheta
Replies: 1
Views: 1087

Re: solve the equation 4 cot^2 x + 12cosecx + 1 = 0 for 0<x<360  TOPIC_SOLVED

hiya thanks for the answer not sure if you have worked it out or not but would the answer be 22.925 and 202.925 or not
thanks for any help
by mannilea
on Wed Sep 09, 2009 8:53 pm
 
Forum: Trigonometry
Topic: solve the equation 4 cot^2 x + 12cosecx + 1 = 0 for 0<x<360
Replies: 4
Views: 2351

Re: solve the equation 4 cot^2 x + 12cosecx + 1 = 0 for 0<x<360  TOPIC_SOLVED

o right thank you didnt think of testing it lol
by mannilea
on Wed Sep 09, 2009 10:28 pm
 
Forum: Trigonometry
Topic: solve the equation 4 cot^2 x + 12cosecx + 1 = 0 for 0<x<360
Replies: 4
Views: 2351

finding stationary points using differentiation

hiya not sure where this should go so sorry if it is in the wrong place

curve is y=(2-x)(x+1)^2

show that one stationary point is at x=-1

find the coordinates if both stationary points

any help much appreciated
by mannilea
on Mon Oct 19, 2009 7:35 pm
 
Forum: Calculus
Topic: finding stationary points using differentiation
Replies: 1
Views: 1692

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