- Wed Aug 26, 2009 1:26 am
- Forum: Beginning Algebra
- Topic: 4^(2X)=10: solve for value of X in exponent
- Replies:
**5** - Views:
**3230**

Use a log base 10. :lol: Here are the steps. :idea: 4^2x=10 2x log^10 4=10 2x=10/log 4 x=(10/ log 4) /2 :shock: But I am 12, so I could be wrong In math and science, your age is not important. The right answer is the right answer, no matter how old you are. In your case though, you forgot to take t...

- Sat Aug 15, 2009 8:49 pm
- Forum: Intermediate Algebra
- Topic: Domain and Range of f = 2x+1, x < 0; f = 2x+2, x >= 0
- Replies:
**4** - Views:
**13810**

My bad. I should have explain that part. (a) and (b) are just 2 extra parts of the question. f(x)= {2x+1 , x <0 f(x)= {2x+2, x >=0 (x is greater or equal to 0) I believe I would just do this, replace x with the number 1 for part (a), and then find the range and domain. Which I do not know how to? f...

- Fri Aug 14, 2009 1:05 am
- Forum: Intermediate Algebra
- Topic: Help! Summer work for Pre-Calc, Completing the square
- Replies:
**7** - Views:
**2253**

C'mon stapel, you wouldn't have this problem if you just installed that mind-reading software plugin for the website.

QM

QM

- Thu Aug 13, 2009 6:43 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: logarithm stumper
- Replies:
**2** - Views:
**1930**

I found this puzzle on another site and spent several hours on it, and am utterly humbled by it! I don't even know if it is really solvable, but I'm guessing it is and I just can't figure this out. Note, I know how to apply the change of base formula, and have tried every permutation I can think of ...

- Thu Aug 13, 2009 6:30 pm
- Forum: Intermediate Algebra
- Topic: and/or inequalities: solution set for -4x>2 and x+1>6
- Replies:
**1** - Views:
**1519**

"and" indicates a "conjunction", which means both equations have to be satisfied in the solution set. First, solve each inequality for x. Then, graph each on it's own number line, one on top of the other. Then, look where the graphs of *both* number lines are the same, and that w...

- Thu Aug 13, 2009 1:08 am
- Forum: Intermediate Algebra
- Topic: Finding the domain of radical, rational, polynomial fcns
- Replies:
**2** - Views:
**2992**

I was wondering if I did this part of my homework correctly. Thanks your input would be greatly appreciated. :) State the domain of the following: :) g(x)=(2x+1)/(x-7) domain= all numbers x different form 0 e) m(x)=3/(x^2+7) domain = all numbers x different from 0 Well, as they say, you're "ge...

- Thu Aug 13, 2009 12:57 am
- Forum: Arithmetic
- Topic: math: why does -3(-3) = +3? how is this solved?
- Replies:
**2** - Views:
**2294**

Hello, I have a quick question. why does -3(-3) = +3 how is this solved? thx. Is this supposed to be a multiplication problem? I.e, are you multiplying negative 3 by itself? If so, then your equation is not correct. If you just ignore the minus sign for the moment, what is 3 times 3? It's not 3! Wh...

- Wed Aug 12, 2009 12:17 am
- Forum: Beginning Algebra
- Topic: Solve 2^2+5x+6 =-x^2-2x for x by factoring
- Replies:
**4** - Views:
**3111**

You want to combine like terms and get everything on one side of the equation, to end up with something in the form of

ax^2 + bx + c = 0

Then you can factor this equation using the various procedures for factoring a quadratic equation.

QM

ax^2 + bx + c = 0

Then you can factor this equation using the various procedures for factoring a quadratic equation.

QM

- Tue Aug 11, 2009 8:15 pm
- Forum: Arithmetic
- Topic: math: don't understand how to simplify | 2 + 3 ( -4 )
- Replies:
**2** - Views:
**2652**

Is this an absolute value problem? If so the last line of the absolute value symbol was left out of your original problem. I'm going to assume this is supposed to be |2+3(-4)| First, just solve the inside part of the absolute value, i.e., 2+3(-4) Do you know how to solve this? Then remember the defi...

- Tue Aug 11, 2009 7:19 am
- Forum: Intermediate Algebra
- Topic: Quadratic form help: x^2 - 3x + 1 = 0
- Replies:
**4** - Views:
**2060**

It looks like you are trying to use the quadratic formula. I would suggest first you review it here: http://www.purplemath.com/modules/solvquad4.htm Next, double check the formula, and what you are using as values for A, B, and C. It usually helps to actually write down these values at the top of yo...