- Thu Aug 06, 2009 4:05 pm
- Forum: Calculus
- Topic: finding delta for limits: prove lim, x->2, x^2 equals 4
- Replies:
**1** - Views:
**10384**

hi all, i'm working on some problems at calc on the web. The limit of x 2 as x approaches 2 is 4. That is, lim x -> 2 x 2 = 4 Let epsilon= 0.2. Find delta > 0 such that if | x - 2 | < delta then | x 2 - 4 | < 0.2 so far i've plugged f(x), L and epsilon into f(x)-L > epsilon to get: x 2 -4 < 1/5, and...

- Wed Aug 05, 2009 11:31 pm
- Forum: Calculus
- Topic: finding limits with square roots in function
- Replies:
**3** - Views:
**9595**

fantastic, thanks! i'll review the whole multiplying by the conjugate thing also.

- Wed Aug 05, 2009 8:49 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: help with some questions (solving logarithmic equations)
- Replies:
**4** - Views:
**2404**

ah, logs aren't defined for negatives...

- Wed Aug 05, 2009 8:47 pm
- Forum: Calculus
- Topic: finding limits with square roots in function
- Replies:
**3** - Views:
**9595**

hi all, i've got a couple problems i'm working on that require you to find the limit of a function with square roots. i'm having some issues with it. if anyone could lend a hand on the following problem it would be most appreciated: lim x->2 (sqrt(2x)-x)/(x-2) i know i need to factor out x-2 but i d...

- Tue Aug 04, 2009 7:17 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: help with some questions (solving logarithmic equations)
- Replies:
**4** - Views:
**2404**

awesome, thanks. so i think i understand the first two but for the last one i'm still hung up. put all the terms on one side and set equal to "0" but i'm getting hung up on the rational roots test. -2 is the constant and 1 is the leading coefficient. so that leaves a possible solution set ...

- Tue Aug 04, 2009 1:29 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: help with some questions (solving logarithmic equations)
- Replies:
**4** - Views:
**2404**

hi, i'm trying to bone up on my pre-calc and calc for a placement exam in a couple weeks. the school gave me some guidance on review and one of the sites they reference is "calculus on the web" which is supported by temple univ. in the logarithmic equations section of their pre-calculus bo...