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by odysseus
Thu Dec 02, 2010 1:03 pm
Forum: Pre-Algebra
Topic: linear equation: solve 4(1 - p) = 3(p - 2), and check answer
Replies: 1
Views: 2095

Re: linear equation: solve 4(1 - p) = 3(p - 2), and check an

555 wrote:Solve. and check by answer
4(1-p)= 3(p-2) :clap:

First do the parentheses; the left side would be 4(1) + 4(-p) = 4 - 4p. Then solve like they show here: add 4p to both sides, add 6 to both sides, and then divide thru.
by odysseus
Tue Sep 14, 2010 11:15 am
Forum: Advanced Algebra ("pre-calculus")
Topic: given u=-28.593*ln(k)+144.76, empirically define c, j
Replies: 1
Views: 1629

Re: given u=-28.593*ln(k)+144.76, empirically define c, j

u = -28.593*ln(k) + 144.76 The object is to empirically define "c" and "j" in the following equation by back substitution: u = c*ln(j/k) ; only valid where k approaches j You can use log rules to take the multiplier out front of the logarithmic term inside as an exponent. Then y...
by odysseus
Mon Jun 07, 2010 12:18 am
Forum: Pre-Algebra
Topic: proportional or non proportional? 2Gb holds 250, 40Gb holds
Replies: 1
Views: 1564

Re: proportional or non proportional? 2Gb holds 250, 40Gb ho

What did you get when you did the cross-multiplication and compared the results? :?:
by odysseus
Sat May 01, 2010 8:34 pm
Forum: Intermediate Algebra
Topic: absolute value quadratic inequalities
Replies: 1
Views: 2460

Re: absolute value quadratic inequalities

Do the graph of the quadratic. Anywhere it's below the axis is negative, so re-draw that part upside-down so it's above the axis. Solve x^2-1=0 to find where the original graph crosses the axis and where the new graph touches. Where x^2-1 was positive anyway, solve x^2-1<2. Where x^2-1 was negative ...
by odysseus
Mon Apr 12, 2010 10:48 pm
Forum: Intermediate Algebra
Topic: How do I determine the coordinates of the vertex ?
Replies: 1
Views: 994

Re: How do I determine the coordinates of the vertex ?

With the equation 4(x-2)(x+6) , how would I determine the coordinates of the vertex ? One way is to multiply out the two factors (not the 4) and then use the formula they give here . A "cheat" way is to remember that the vertex is midway between the two x-intercepts. So use the two factor...
by odysseus
Tue Feb 23, 2010 12:41 pm
Forum: Intermediate Algebra
Topic: Help Adding Rational Expressions
Replies: 3
Views: 1539

Re: Help Adding Rational Expressions

-2 + 4y + 6 ------- ------- ----- LCD = (y+3) (y-3) (y-3) y^2 - 9 (y-3)^2 3-y -2 + 4y + 6 ---------- ---------- ------- (y+3)(y-3) (y-3)(y-3) -1(3-y) The denominator 3 - y is not equal to -1(3 - y); it is equal to -y + 3 = -y - (-3) = -(y - 3). Then you can put the negative on the 6.
by odysseus
Sun Jan 31, 2010 1:16 pm
Forum: Beginning Algebra
Topic: Finding the principal invested
Replies: 1
Views: 1527

Re: Finding the principal invested

Use the set-up they show here: http://www.purplemath.com/modules/investmt.htm
by odysseus
Fri Sep 18, 2009 1:40 pm
Forum: Discrete Math
Topic: are any sequences both arithmetic and geometric?
Replies: 1
Views: 2574

are any sequences both arithmetic and geometric?

Are there any sequences which are both arithmetic and geometric? I don't think so, but how would I prove this?
by odysseus
Tue Sep 08, 2009 4:52 pm
Forum: Uncategorized
Topic: How many metres would the pony cover when taking 24 steps?
Replies: 1
Views: 1770

How many metres would the pony cover when taking 24 steps?

A horse takes three steps to walk the same distance for which a pony takes four steps. Suppose that one step of the horse covers a half-metre. How many metres would the pony cover when taking twenty-four steps? I keep tying myself in knots, getting nowhere. Any ideas for an intelligent start on this...
by odysseus
Mon Jul 27, 2009 6:32 pm
Forum: Matrix (Linear) Algebra
Topic: vet designs special diet for cat.... Find least-cost mix
Replies: 2
Views: 4046

Yes, that made plenty of sense. Thank you for your time.

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