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Re: finding roots for x4 - 5x^2 + 6 = 0  TOPIC_SOLVED

As written, this looks like the quadratic: -5x^2 + 4x + 6 = 0 But quadratic equations have at most two real solutions. You list four roots. This leads me to think there is a typo in your equation and that it should be: x^4 - 5x^2 + 6 = 0 . Since this is a quartic, it can indeed have four solutions. ...
by Honeysuckle588
on Wed Jul 15, 2009 6:26 pm
 
Forum: Advanced Algebra ("pre-calculus")
Topic: finding roots for x4 - 5x^2 + 6 = 0
Replies: 10
Views: 7596

Re: finding roots for x4 - 5x^2 + 6 = 0  TOPIC_SOLVED

Hi Jesse, A little easier in this case for the quartic. Define a new variable, such as u = x^2. Then u^2 = x^4. So now the equation can be written as: u^2 - 5u + 6 = 0. This is quadratic in u, and factorable. Solve for u. Then substitute x^2 into your solutions and solve the resulting two quadratics...
by Honeysuckle588
on Wed Jul 15, 2009 7:12 pm
 
Forum: Advanced Algebra ("pre-calculus")
Topic: finding roots for x4 - 5x^2 + 6 = 0
Replies: 10
Views: 7596

Re: Geometry Word Problems: The Pythagorean Theorem  TOPIC_SOLVED

The half-meter is added to each end. So 5 + 1/2 + 1/2 = 6.
by Honeysuckle588
on Fri Jul 17, 2009 4:18 am
 
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 3241

Re: New Lessons?

Do you ever enlist help with the lessons?
by Honeysuckle588
on Fri Jul 17, 2009 12:16 pm
 
Forum: News
Topic: New Lessons?
Replies: 9
Views: 10882

Re: Geometry Word Problems: The Pythagorean Theorem  TOPIC_SOLVED

Interesting. According to one of the online dictionaries that I just consulted, when either is used as an adjective (as in this case) it can mean 1. Any one of two; one or the other: wear either coat. 2. One and the other; each: rings on either hand. So you interpreted it in the first sense, and I i...
by Honeysuckle588
on Fri Jul 17, 2009 12:22 pm
 
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 3241

Re: New Lessons?

Do you invite/welcome suggestions for edits (formatting, presentation, etc.) from qualified individuals? Or are such interlopers frowned upon?
by Honeysuckle588
on Fri Jul 17, 2009 7:39 pm
 
Forum: News
Topic: New Lessons?
Replies: 9
Views: 10882

Re: Conics  TOPIC_SOLVED

For whatever reason, your equation is not rendering on my machine. How did you type it in?
by Honeysuckle588
on Sat Jul 18, 2009 1:19 pm
 
Forum: Calculus
Topic: Determine eqn of conic, given F(3,1), directrix x-1=>0, ecc.
Replies: 9
Views: 4163

Re: formula 0.5 * b * c * sin(A) allows you to find the area of  TOPIC_SOLVED

I oriented my triangles with the side b along the horizontal (the initial side of angle A), and the side c as the terminal side. Then, drop a perpendicular line from the end of c down to the line that b sits on. It shouldn't take long for you to determine that the length of this vertical line is c s...
by Honeysuckle588
on Sat Jul 18, 2009 7:09 pm
 
Forum: Trigonometry
Topic: formula 0.5 * b * c * sin(A) allows you to find the area of
Replies: 2
Views: 1847

Re: find sruface area of sphere with cube inside with edge=1  TOPIC_SOLVED

In order to find the surface area of the sphere, you need to find know its radius. You will use the cube to determine the radius of the sphere. Since the cube is inscribed in the sphere, the center of the cube and the center of the sphere coincide. Also, since the cube is inscribed inside the sphere...
by Honeysuckle588
on Mon Jul 20, 2009 12:19 pm
 
Forum: Geometry
Topic: find sruface area of sphere with cube inside with edge=1
Replies: 6
Views: 3801

Re: A non linear system: x+y+z=2, x^2+y^2+z^2=14, x^4+y^4+z^4=98  TOPIC_SOLVED

Well...graphing it showed me there are 6 points that solve the system. Can you first determine the intersection of the plane and the sphere? It's a circle, and if you can get the equation for that you can then work on finding the intersection of the circle with the cube-like 4th degree.
by Honeysuckle588
on Mon Jul 20, 2009 12:23 pm
 
Forum: Advanced Algebra ("pre-calculus")
Topic: A non linear system: x+y+z=2, x^2+y^2+z^2=14, x^4+y^4+z^4=98
Replies: 3
Views: 2127
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