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Re: THINK + RETHINK = REFLECT (each letter stands for a number)  TOPIC_SOLVED

I need to find the numbers for each letter in "THINK + RETHINK = REFLECT". Bear in mind that there may be more than one solution, as some numbers may swap places without affecting any other numbers. This can occur when you have two sets of adjacent (side-by-side) columns that behave the s...
by DAiv
on Tue Dec 16, 2008 8:05 pm
 
Forum: Arithmetic
Topic: THINK + RETHINK = REFLECT (each letter stands for a number)
Replies: 2
Views: 3653

Re: find normal and overtime rates of pay for carpenter  TOPIC_SOLVED

If I times the second one by 3, I get 81 normal hours and 9 overtime hours for $189. This is 60 more normal hours and $120 more dollars, for $2 for each normal hour. Working backwards, I get 69 - 21*2 = 27, so each overtime hour is $3. This answer works, but it seems too easy. Am I doing this wrong...
by DAiv
on Wed Dec 17, 2008 12:57 pm
 
Forum: Pre-Algebra
Topic: find normal and overtime rates of pay for carpenter
Replies: 3
Views: 4024

Re: Help please  TOPIC_SOLVED

This site has lots of useful information on how to solve such problems in the Beginning Algebra Topics section. In particular, Solving Linear Equations Slope of a Straight Line Slope and y-intercept Intercepts Have a read through those and hopefully things will be a little clearer. DAiv
by DAiv
on Wed Dec 17, 2008 8:21 pm
 
Forum: Pre-Algebra
Topic: solve 3x-6y=18 for y; show (2,4) soln for 3x+4y=22; slopes &
Replies: 3
Views: 9092

Re:  TOPIC_SOLVED

(20)(2x)+(10)(3x)+(1x) 30+6x=285 How did you arrive at "30 + 6x" from "40x + 30x + 1x"? . . . . . Simplifying with Parentheses Please reply with the steps between your two quoted lines above. Thank you! :D Eliz. I hope I'm not stepping on any toes, but I think I can see what has...
by DAiv
on Thu Dec 18, 2008 1:45 am
 
Forum: Beginning Algebra
Topic: coin and interest math problem help
Replies: 4
Views: 4038

Re: Stuying for the TEAS Test: EqA (K = y/x), enzyme reactions

I derive half the fun of answering some questions from working out what the original question actually was. :wink: I think there must have been two graphs, entitled "Enzyme Activity as a Function of Time". Equation A was "k = y/x", and Equation B was something else, perhaps "...
by DAiv
on Thu Dec 18, 2008 9:10 am
 
Forum: Uncategorized
Topic: Stuying for the TEAS Test: EqA (K = y/x), enzyme reactions
Replies: 2
Views: 4462

Re: solve 3x-6y=18 for y; show (2,4) soln for 3x+4y=22; slopes &  TOPIC_SOLVED

Q1. Given the following equation, 3x – 6y = 18; solve for y. Looks good and the working is well laid out and easy to follow. :D Be careful, though, when writing variables to make sure that if you start with a lower case variable, it remains lower case throughout. For example, y does not become Y, s...
by DAiv
on Thu Dec 18, 2008 5:35 pm
 
Forum: Pre-Algebra
Topic: solve 3x-6y=18 for y; show (2,4) soln for 3x+4y=22; slopes &
Replies: 3
Views: 9092

Re: Limit approaching infinity with an unknown in the exponent  TOPIC_SOLVED

Find the limit, as x approaches infinity, of (1+(2/x)) x This is a problem from Temple University's 'Calculus on the Web' site, I am trying to get re-acquainted with first-semester Calculus as I will begin taking Calc II in a month from now. I can't think of how to bring that x down. Logs? Do you n...
by DAiv
on Sat Dec 20, 2008 10:45 am
 
Forum: Calculus
Topic: Limit approaching infinity with an unknown in the exponent
Replies: 7
Views: 8573

Re: Limit approaching infinity with an unknown in the exponent  TOPIC_SOLVED

jimmy_boots wrote:2 divided by infinity goes to 0. 1 plus 0 is one. One raised to infinity is an indeterminate form, hence my wish to change the nature of the exponent x.



DAiv
by DAiv
on Sat Dec 20, 2008 3:44 pm
 
Forum: Calculus
Topic: Limit approaching infinity with an unknown in the exponent
Replies: 7
Views: 8573

Re: Limit approaching infinity with an unknown in the exponent  TOPIC_SOLVED

That's not helping me dave. It looks good intuitively but 1 is not a valid answer. I repeat, one raised to infinity is considered an indeterminate form. You're right, it's not a simple solution. Q. Find \lim_{x\to\infty}\left(1+\frac2x\right)^x There are at least two ways of solving this, a...
by DAiv
on Tue Dec 23, 2008 3:32 pm
 
Forum: Calculus
Topic: Limit approaching infinity with an unknown in the exponent
Replies: 7
Views: 8573

Re: [SPLIT] -9x - 4 > 50 (don't know how to do this)  TOPIC_SOLVED

alejandra wrote:please help me i dont know how to do this

-9x-4>50

Hi Alejandra

The Inequalities: Linear section explains how to solve inequalities like this.

DAiv
by DAiv
on Tue Dec 30, 2008 12:15 am
 
Forum: Pre-Algebra
Topic: [SPLIT] -9x - 4 > 50 (don't know how to do this)
Replies: 3
Views: 4465
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