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purplemath.org

There is a library at a college near my home that has public computers for non-students. However, the uses are restricted for the public users. Only websites that end in .edu,.org, and .gov can be accessed. Would there be a way you could make it so I could access your site. For instance could you ma...
by Jesse
on Wed Jul 15, 2009 4:59 pm
 
Forum: News
Topic: purplemath.org
Replies: 1
Views: 4821

Re: finding roots for x4 - 5x^2 + 6 = 0  TOPIC_SOLVED

There cannot be four roots. If you are dealing with a quadratic equation, then you can have 2 roots at most. You can use the discriminant to determine what type of roots you have. The discriminant is the "b^2-4ac" part of the quadratic equation. There are three cases: If b^2-4ac > 0 , then...
by Jesse
on Wed Jul 15, 2009 6:38 pm
 
Forum: Advanced Algebra ("pre-calculus")
Topic: finding roots for x4 - 5x^2 + 6 = 0
Replies: 10
Views: 7989

Re: finding roots for x4 - 5x^2 + 6 = 0  TOPIC_SOLVED

That works great for this problem. That reminds me, the first thing you should do when attempting to find zeros (if possible) is to try and use factoring techniques (special products, factoring by grouping, etc.)
by Jesse
on Wed Jul 15, 2009 7:31 pm
 
Forum: Advanced Algebra ("pre-calculus")
Topic: finding roots for x4 - 5x^2 + 6 = 0
Replies: 10
Views: 7989

Re: Age Prob: Paul is 7 years older than John. If 13 is added to  TOPIC_SOLVED

P=Paul's age, J=John's age Paul is 7 years older than John. This translates to P= 7+J If 13 is added to Paul’s age... This translates to P+13 ...and 5 is subtracted from John’s age,... This translates to J-5 ...Paul will be twice as old as John. This translates to P+13=2(J-5) Now we have two equatio...
by Jesse
on Wed Jul 15, 2009 8:19 pm
 
Forum: Beginning Algebra
Topic: Age Prob: Paul is 7 years older than John. If 13 is added to
Replies: 4
Views: 4751

New Lessons?

I was curious to see if there were any plans on adding new lessons, or if they are currently in the works. Is there a possiblity that lessons on calculus, statistics, linear algebra, proof writing, or on differential equations may be coming in the near future? I apologize if this has already been ad...
by Jesse
on Thu Jul 16, 2009 11:40 pm
 
Forum: News
Topic: New Lessons?
Replies: 9
Views: 11327

Geometry Word Problems: The Pythagorean Theorem  TOPIC_SOLVED

http://www.purplemath.com/modules/perimetr3.htm ( wooden frame problem, with concrete and crosswire ) End of your solution: 5 = d Adding a half-meter at either end of the wire, I find that: each wire should be cut to a length of six meters I was wondering why the answer is 6 meters, as opposed to 5...
by Jesse
on Fri Jul 17, 2009 12:07 am
 
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 3399

Re: Geometry Word Problems: The Pythagorean Theorem  TOPIC_SOLVED

" Assuming an extra half-meter of wire is used at either end of a cross-wire for anchoring,..."

It states either end, not each end.
by Jesse
on Fri Jul 17, 2009 4:46 am
 
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 3399

Re: Geometry Word Problems: The Pythagorean Theorem  TOPIC_SOLVED

Hmm, that's very interesting, I have never seen either used like that (not either, as in either of the definitions! In that case I would think both!). From the context of the problem it seems that it would be "one or the other". I think many people would interpret it that way. I think if e...
by Jesse
on Fri Jul 17, 2009 4:26 pm
 
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 3399

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