- Fri Jul 17, 2009 4:26 pm
- Forum: Trigonometry
- Topic: Geometry Word Problems: The Pythagorean Theorem
- Replies:
**5** - Views:
**4791**

Hmm, that's very interesting, I have never seen either used like that (not either, as in either of the definitions! In that case I would think both!). From the context of the problem it seems that it would be "one or the other". I think many people would interpret it that way. I think if e...

- Fri Jul 17, 2009 4:46 am
- Forum: Trigonometry
- Topic: Geometry Word Problems: The Pythagorean Theorem
- Replies:
**5** - Views:
**4791**

It states either end, not

- Fri Jul 17, 2009 12:07 am
- Forum: Trigonometry
- Topic: Geometry Word Problems: The Pythagorean Theorem
- Replies:
**5** - Views:
**4791**

http://www.purplemath.com/modules/perimetr3.htm ( wooden frame problem, with concrete and crosswire ) End of your solution: 5 = d Adding a half-meter at either end of the wire, I find that: each wire should be cut to a length of six meters I was wondering why the answer is 6 meters, as opposed to 5...

- Thu Jul 16, 2009 11:40 pm
- Forum: News
- Topic: New Lessons?
- Replies:
**9** - Views:
**13864**

I was curious to see if there were any plans on adding new lessons, or if they are currently in the works. Is there a possiblity that lessons on calculus, statistics, linear algebra, proof writing, or on differential equations may be coming in the near future? I apologize if this has already been ad...

- Wed Jul 15, 2009 8:19 pm
- Forum: Beginning Algebra
- Topic: Age Prob: Paul is 7 years older than John. If 13 is added to
- Replies:
**4** - Views:
**5582**

P=Paul's age, J=John's age Paul is 7 years older than John. This translates to P= 7+J If 13 is added to Paul’s age... This translates to P+13 ...and 5 is subtracted from John’s age,... This translates to J-5 ...Paul will be twice as old as John. This translates to P+13=2(J-5) Now we have two equatio...

- Wed Jul 15, 2009 7:31 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: finding roots for x4 - 5x^2 + 6 = 0
- Replies:
**10** - Views:
**11647**

That works great for this problem. That reminds me, the first thing you should do when attempting to find zeros (if possible) is to try and use factoring techniques (special products, factoring by grouping, etc.)

- Wed Jul 15, 2009 6:38 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: finding roots for x4 - 5x^2 + 6 = 0
- Replies:
**10** - Views:
**11647**

There cannot be four roots. If you are dealing with a quadratic equation, then you can have 2 roots at most. You can use the discriminant to determine what type of roots you have. The discriminant is the "b^2-4ac" part of the quadratic equation. There are three cases: If b^2-4ac > 0 , then...

- Wed Jul 15, 2009 4:59 pm
- Forum: News
- Topic: purplemath.org
- Replies:
**1** - Views:
**5961**

There is a library at a college near my home that has public computers for non-students. However, the uses are restricted for the public users. Only websites that end in .edu,.org, and .gov can be accessed. Would there be a way you could make it so I could access your site. For instance could you ma...