## Search found 7 matches

Fri Jul 17, 2009 4:26 pm
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 5432

### Re: Geometry Word Problems: The Pythagorean Theorem

Hmm, that's very interesting, I have never seen either used like that (not either, as in either of the definitions! In that case I would think both!). From the context of the problem it seems that it would be "one or the other". I think many people would interpret it that way. I think if each was us...
Fri Jul 17, 2009 4:46 am
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 5432

### Re: Geometry Word Problems: The Pythagorean Theorem

" Assuming an extra half-meter of wire is used at either end of a cross-wire for anchoring,..."

It states either end, not each end.
Fri Jul 17, 2009 12:07 am
Forum: Trigonometry
Topic: Geometry Word Problems: The Pythagorean Theorem
Replies: 5
Views: 5432

### Geometry Word Problems: The Pythagorean Theorem

http://www.purplemath.com/modules/perimetr3.htm ( wooden frame problem, with concrete and crosswire ) End of your solution: 5 = d Adding a half-meter at either end of the wire, I find that: each wire should be cut to a length of six meters I was wondering why the answer is 6 meters, as opposed to 5...
Thu Jul 16, 2009 11:40 pm
Forum: News
Topic: New Lessons?
Replies: 9
Views: 15579

### New Lessons?

I was curious to see if there were any plans on adding new lessons, or if they are currently in the works. Is there a possiblity that lessons on calculus, statistics, linear algebra, proof writing, or on differential equations may be coming in the near future? I apologize if this has already been ad...
Wed Jul 15, 2009 7:31 pm
Topic: finding roots for x4 - 5x^2 + 6 = 0
Replies: 10
Views: 14611

### Re: finding roots for x4 - 5x^2 + 6 = 0

That works great for this problem. That reminds me, the first thing you should do when attempting to find zeros (if possible) is to try and use factoring techniques (special products, factoring by grouping, etc.)
Wed Jul 15, 2009 6:38 pm
Topic: finding roots for x4 - 5x^2 + 6 = 0
Replies: 10
Views: 14611

### Re: finding roots for x4 - 5x^2 + 6 = 0

There cannot be four roots. If you are dealing with a quadratic equation, then you can have 2 roots at most. You can use the discriminant to determine what type of roots you have. The discriminant is the "b^2-4ac" part of the quadratic equation. There are three cases: If b^2-4ac > 0 , then there are...
Wed Jul 15, 2009 4:59 pm
Forum: News
Topic: purplemath.org
Replies: 1
Views: 6930

### purplemath.org

There is a library at a college near my home that has public computers for non-students. However, the uses are restricted for the public users. Only websites that end in .edu,.org, and .gov can be accessed. Would there be a way you could make it so I could access your site. For instance could you ma...