## Search found 3 matches

Sun Aug 09, 2009 11:42 pm
Forum: Trigonometry
Topic: Exponets (2)^3 / (2)^-2 ---- ---- (5) (5)
Replies: 2
Views: 1969

### Re: Exponets (2)^3 / (2)^-2 ---- ---- (5) (5)

I thing\k it is pretty clear that the expression is $\frac{2^3/2^{-2}}{(5)(5)}\ =\ \frac{2^{3 -(-2)}}{25}\ =\ \frac{2^5}{25}\ =\ \frac{32}{25}$
Sun Jul 05, 2009 6:20 am
Forum: Geometry
Topic: Chords in circle: If mAD = 58, m<AED = 42, find BC
Replies: 4
Views: 4146

### Re: Chords in circle: If mAD = 58, m<AED = 42, find BC

42 is the mean (average) of the intercepted arcs. (mAD + mBC)/2 = 42. Since we know that mAD = 58, (58 + mBC)/2 = 42, (58 + mBC) = 84, mBC = 26

Polyhymnio
Mon Jun 22, 2009 4:27 am
Forum: Geometry
Topic: Chords in circle: If mAD = 58, m<AED = 42, find BC
Replies: 4
Views: 4146

### Re: Chords in circle: If mAD = 58, m<AED = 42, find BC

The measure of the angle between intersecting chords is equal to the mean of the measures of their intercepted arcs. Since <AED and <BEC are vertical angles, (mAD + mBC)/2 = 42. Then mBC = (42)(2) - 58 = 26

Polyhymnio