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sets: definition of "fraction" raises ambiguity regarding Q  TOPIC_SOLVED

http://www.purplemath.com/modules/setnotn.htm I think the definition of a 'fraction' raises some ambiguity: what is a fraction in terms of what can be defined by \mathbb{Q} ? All integers can be placed in a fraction, 2\over1 . \mathbb{Z} = \mathbb{Q} ? Decimals can convert to fractions, are they de...
by Tennise
on Sat Jun 06, 2009 6:44 pm
 
Forum: Uncategorized
Topic: sets: definition of "fraction" raises ambiguity regarding Q
Replies: 6
Views: 3135

Re:  TOPIC_SOLVED

Thanks for your responses, Any value which can be expressed as a ratio of integers will belong in \mathbb{Q} . This clarifies it for the most part, just one thing: recurring non-repeating decimals can't accurately be placed in a fraction, would these be exceptions or would they be included in \mathb...
by Tennise
on Sat Jun 06, 2009 9:11 pm
 
Forum: Uncategorized
Topic: sets: definition of "fraction" raises ambiguity regarding Q
Replies: 6
Views: 3135

Re: sets: definition of "fraction" raises ambiguity regarding Q  TOPIC_SOLVED

I see, thanks!

hmm, I saw a button on here to mark the thread as "solved" before but it seems to have disappeared...
by Tennise
on Sat Jun 06, 2009 10:15 pm
 
Forum: Uncategorized
Topic: sets: definition of "fraction" raises ambiguity regarding Q
Replies: 6
Views: 3135

simple factoring: (x^2)(y^3)+xy  TOPIC_SOLVED

I understand the numerical ones, but am having trouble with the variable ones... It works in theory, and I can see how it would work, but when I substitute numbers for the variables, it doesn't work: x = 2, y = 3 This was the expression: x 2 y 3 +xy 4*27+6 = 114 This was the answer: xy(xy 2 + 1) 6(2...
by Tennise
on Mon Jun 08, 2009 8:58 pm
 
Forum: Beginning Algebra
Topic: simple factoring: (x^2)(y^3)+xy
Replies: 3
Views: 1970

Re: simple factoring: (x^2)(y^3)+xy  TOPIC_SOLVED

I understand the numerical ones, but am having trouble with the variable ones... It works in theory, and I can see how it would work, but when I substitute numbers for the variables, it doesn't work: x = 2, y = 3 This was the expression: x 2 y 3 +xy 4*27+6 = 114 This was the answer: xy(xy 2 + 1) 6(...
by Tennise
on Mon Jun 08, 2009 9:10 pm
 
Forum: Beginning Algebra
Topic: simple factoring: (x^2)(y^3)+xy
Replies: 3
Views: 1970

[MOVED] roots and the least common denominator  TOPIC_SOLVED

To find the least common denominator of {2 \over 3a}+{4 \over a^2} the book I'm reading says to multiply them to get a common denominator of 3a^2: {2a \over 3a^2}+{12 \over 3a^2} = {2a+12 \over 3a^2} But wouldn't it be more efficient to find the square roots of the second fraction before multiplying...
by Tennise
on Tue Jun 23, 2009 4:20 pm
 
Forum: Beginning Algebra
Topic: [MOVED] roots and the least common denominator
Replies: 2
Views: 1371

Re: roots and the least common denominator  TOPIC_SOLVED

Oh, I see now... Thought I could cheat my way through and remove the exponent by squaring, guess not! Thanks for your help, and the link, although my problem wasn't LCM/GCF here :P Edit: I just noticed you moved this thread, sorry for posting in the wrong area, arithmetic's description listed fracti...
by Tennise
on Tue Jun 23, 2009 6:51 pm
 
Forum: Beginning Algebra
Topic: [MOVED] roots and the least common denominator
Replies: 2
Views: 1371

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