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[SPLIT] A company installs underground cable for $500 for 1st 50  TOPIC_SOLVED

hello!!! I have a word problem of which I do not understand. A company installs underground cable at a cost of $500 for the first 50ft and $5 for each additional foot thereafter. Express the cost C as a function of the length L of underground cable if L >50ft do anyone have a master technique that I...
by starr
on Tue Feb 03, 2009 12:12 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] A company installs underground cable for $500 for 1st 50
Replies: 8
Views: 3464

Re: [SPLIT] A company installs underground cable for $500 for 1s  TOPIC_SOLVED

hello eliz!!!!

I see your point!!! my problem is I am not sure how to set up the fuction.
by starr
on Tue Feb 03, 2009 1:12 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] A company installs underground cable for $500 for 1st 50
Replies: 8
Views: 3464

Re: [SPLIT] A company installs underground cable for $500 for 1s  TOPIC_SOLVED

hello eliz!!!

the calculation I came up with is

c=5l +500

I dont think that's quite right
by starr
on Tue Feb 03, 2009 1:31 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] A company installs underground cable for $500 for 1st 50
Replies: 8
Views: 3464

Re: [SPLIT] A company installs underground cable for $500 for 1s  TOPIC_SOLVED

my reasoning for the formula was simple. 500for the first 50 ft and 5 times for the extra length.
I see a pattern of which as the length increase by five. Is that what you referring to???
by starr
on Tue Feb 03, 2009 2:23 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] A company installs underground cable for $500 for 1st 50
Replies: 8
Views: 3464

Re: [SPLIT] A company installs underground cable for $500 for 1s  TOPIC_SOLVED

at some point L has to be greater than 50
by starr
on Tue Feb 03, 2009 2:44 pm
 
Forum: Beginning Algebra
Topic: [SPLIT] A company installs underground cable for $500 for 1st 50
Replies: 8
Views: 3464

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