The Purplemath Forums

Am I doing this the right way? Is there a faster way of doing this? Thanks. You're doing this exactly the right way. No, I'm not familiar with any "faster" way. Just keep going like you are. You have found that T must be 2 or 4. Each of these options is a "case". So test the &qu...

I think this gives me y^2 - 7y - 8 = 0. Is that right? That's exactly right! :wink: Now factor, and set each factor equal to zero. Once you've done that, plug the 2^x back in for the y, and use what you know about powers to find the answers. If you get stuck, please reply showing how far you got. T...

My thinking: Since the average of the 8 numbers is 3, and you find this average by dividing the total by 8, then that total is 8*3 = 24, right? So would the total of the others be 12*x, with the combined total being 20*9 = 180? And then you add the two smallers numbers and make this equal to the co...

little_dragon wrote:Is this the right way to set it up? Do I do the trig ratios and use my calculator to find how tall he is?

Sounds good to me!

Eliz.

They've given you the first three factors at the beginning, but only one at the end. Try writing out the factors from the end, working backwards from (x - z)....

Eliz.

It would appear that the "Pre" tags work better than the "code" tags...?

At least, I can certainly read the results better!

Eliz.

Do you do problems such as: EqA (K =y/x) Um... I don't know. What is "EqA (K =y/x)"? What do the variables and equation represent, and what are you supposed to do with them? :oops: Here is an example problem. 100 80 o 60 o 40 o 20 o 2 4 6 8 10 Product (u moles) Time(minutes)Enzyme Activit...

This answer works, but it seems too easy. Am I doing this wrong? You're only "doing it wrong" if you were told to use some particular other method (such as a system of equations). :wink: What you have done is logical, and it leads to the correct answer. I would think that, as long as you ...

LateX (pronounced "LAY-teck"): . . . . . [t ex]\left[ \begin{array} {rrr} 1&2&3 \\ 4&5&6 \\ 7&8&9 \end{array} \right][/tex] ...produces: . . . . . \left[ \begin{array} {rrr} 1&2&3 \\ 4&5&6 \\ 7&8&9 \end{array} \right] ...while: . . . . . [pre...

36: Find the limit: lim, x -> 0, (sin 4x)/(sin 6x) I'm pretty sure I need to use the fact that lim, x->0, (sin x)/(x) = 1.... You're exactly right about the tool you need to use. There's a bit of a trick to setting it up, though. For the moment, let's leave off the "limit" bit, and just d...