- Wed Dec 17, 2008 6:17 pm
- Forum: Beginning Algebra
- Topic: coin and interest math problem help
- Replies:
**4** - Views:
**5950**

I've been sick and away from school and my teacher sent me 4 problems and I can't figure them out. It can be hard to try to work just from the book and whatever class notes your friends have sent home. :shock: To learn some of the general background material, try here: . . . . . Translating Word Pr...

- Tue Dec 16, 2008 12:32 pm
- Forum: Advanced Algebra ("pre-calculus")
- Topic: find the constant c that makes g continuous (g in two parts)
- Replies:
**1** - Views:
**13339**

- Sun Dec 14, 2008 1:58 pm
- Forum: Matrix (Linear) Algebra
- Topic: formatting matrices using LaTeX and 'pre' tags
- Replies:
**0** - Views:
**4299**

LateX (pronounced "LAY-teck"): . . . . . [t ex]\left[ \begin{array} {rrr} 1&2&3 \\ 4&5&6 \\ 7&8&9 \end{array} \right][/tex] ...produces: . . . . . \left[ \begin{array} {rrr} 1&2&3 \\ 4&5&6 \\ 7&8&9 \end{array} \right] ...while: . . . . . [pre...

- Sun Dec 14, 2008 1:41 pm
- Forum: Pre-Algebra
- Topic: find normal and overtime rates of pay for carpenter
- Replies:
**3** - Views:
**5730**

- Wed Dec 10, 2008 7:35 pm
- Forum: Forum Rules & Guides
- Topic: trying out some of the formatting
- Replies:
**4** - Views:
**5560**

- Wed Dec 10, 2008 6:27 pm
- Forum: Discrete Math
- Topic: find value of (x - a)(x - b)(x - c) ... (x - z)
- Replies:
**2** - Views:
**6368**

- Wed Dec 10, 2008 12:36 am
- Forum: Trigonometry
- Topic: angle of depression and how tall is romeo
- Replies:
**1** - Views:
**4669**

- Tue Dec 09, 2008 9:40 pm
- Forum: Statistics
- Topic: mean of 8 numbers is 3, mean of 12 is x, mean of all is 9
- Replies:
**2** - Views:
**4460**

My thinking: Since the average of the 8 numbers is 3, and you find this average by dividing the total by 8, then that total is 8*3 = 24, right? So would the total of the others be 12*x, with the combined total being 20*9 = 180? And then you add the two smallers numbers and make this equal to the co...

- Mon Dec 08, 2008 6:29 pm
- Forum: Beginning Algebra
- Topic: Solve 2^(2x) - 7(2^x) - 8 = 0 (Hint: Let y = 2^x)
- Replies:
**1** - Views:
**4560**

I think this gives me y^2 - 7y - 8 = 0. Is that right? That's exactly right! :wink: Now factor, and set each factor equal to zero. Once you've done that, plug the 2^x back in for the y, and use what you know about powers to find the answers. If you get stuck, please reply showing how far you got. T...

- Mon Dec 08, 2008 6:17 pm
- Forum: Arithmetic
- Topic: THINK + RETHINK = REFLECT (each letter stands for a number)
- Replies:
**2** - Views:
**5125**