## Search found 13 matches

Wed Apr 14, 2010 3:23 pm
Forum: Arithmetic
Replies: 1
Views: 2270

Hello, I am trying to figure out this problem: If 5^n + 5^n + 5^n + 5^n + 5^n = 5^25 then what is the integer n that satisfies this equation? I know that when adding exponents, I do not add the exponents together. Instead I add the base with its exponent to the other bases with their exponents. I kn...
Sun May 31, 2009 2:46 pm
Forum: Intermediate Algebra
Topic: Using the formula x^2 - (r1 + r2)x + (r1 * r2) = 0
Replies: 3
Views: 2408

### Re: Using the formula x^2 - (r1 + r2)x + (r1 * r2) = 0

Great! I'm happy I got those right. But, unfortunately they get harder. #3 2/3, -3/5 I forgot how to add and multiply fractions. :oops: I think I need a common denominator to add so that would be 15. And Idk about multiplying. Just multiply the numerator 2 with the other numerator -3. And just multi...
Sun May 31, 2009 1:07 am
Forum: Intermediate Algebra
Topic: Using the formula x^2 - (r1 + r2)x + (r1 * r2) = 0
Replies: 3
Views: 2408

### Using the formula x^2 - (r1 + r2)x + (r1 * r2) = 0

Can anyone who understands this well take a minute and check my work and see if I did this right? :oops: The book says: Use the form x^2 - (r1 + r2)x + (r1 * r2)=0 Write a quadratic equation having the given roots. Problem #1 5,-3 My Work: Sum of roots: 5+(-3)= 2 Product of roots: 5*-3= -15 so... an...
Sun May 31, 2009 12:57 am
Forum: Intermediate Algebra
Topic: [SPLIT] finding vertex, direction from y=ax^2+bx+c
Replies: 2
Views: 1454

### Re: [SPLIT] finding vertex, direction from y=ax^2+bx+c

OKay Thanks You once again I got that now too.
Thu May 28, 2009 10:52 pm
Forum: Intermediate Algebra
Topic: [SPLIT] finding vertex, direction from y=ax^2+bx+c
Replies: 2
Views: 1454

### [SPLIT] finding vertex, direction from y=ax^2+bx+c

My next section is a bit different and once again I have no clue what to do. In the book it says :

"Find the coordinates of the vertex then decide if the parabola has a minimum or maximum value."

Ex.1
f(x) = x^2 - 4x + 4

Ex. 2
f(x) = -x^2 - 8x - 16

Can you tell me what to do here?
Thu May 28, 2009 8:58 pm
Forum: Intermediate Algebra
Topic: Graphing Quadratic Functions (vertex formula)
Replies: 3
Views: 3145

### Re: Graphing Quadratic Functions (vertex formula)

Thanks stapel for the simple explanation. Here's the work I did for the 1st example. y = a(x - h)^2 + k 7 = a(4 - 3)^2 + 5 7 = a(1)^2 +5 7= a + 5 2 = a And the final answer is: y = 2(x-3)^2 + 5 For the second one I got 1/2 = a and the final answer/equation is: y = 1/2(x - (-1))^2 + 1 Are these corre...
Thu May 28, 2009 7:01 pm
Forum: Intermediate Algebra
Topic: Graphing Quadratic Functions (vertex formula)
Replies: 3
Views: 3145

### Graphing Quadratic Functions (vertex formula)

I am having a really hard time with this section. My teacher will be absent tomorrow and I have a test on Monday. I don't understand this. So, for practice could anyone help me out and show me step by step how to do some problems? In my book, it says: "use the Vertex Form: y - k = a (x - h)^2 Write ...
Thu May 21, 2009 1:25 am
Forum: Intermediate Algebra
Replies: 5
Views: 2401

Wait I'm confused. For 2(x-1)^2+7(x-1)+6=0 shouldn't I be looking for factors of 6 and not 12?

And for, 2x-9sqrt(x)+4=0, don't i need factors of 4 and not 8 ?

Thanks..
Wed May 20, 2009 7:47 pm
Forum: Intermediate Algebra
Replies: 5
Views: 2401

Thanks for your help, stapel.. Here's what I got for the first one, x= i sqrt(5) and x=sqrt(3) i being the imaginary number of sqrt(-1) I'm not sure it is correct though :oops: For the second one, I can't seem to get the factors to add up to 7y (the middle term) so I'm stuck here I want to do (2z+1)...
Wed May 20, 2009 5:11 pm
Forum: Intermediate Algebra
Replies: 5
Views: 2401