- Tue May 19, 2015 5:47 pm
- Forum: Discrete Math
- Topic: Probability Question
- Replies:
**1** - Views:
**20**

...9% of men are color blind. For four randomly selected men, find the probability that a. the first three are not color blind and the fourth is color blind? For any random guy, what is the probability that he's color-blind? What is the probability that he is not color-blind? Does one random guy's ...

- Sun May 17, 2015 12:48 am
- Forum: Intermediate Algebra
- Topic: How to reduce this rational expression to its lowest term?
- Replies:
**2** - Views:
**33**

\dfrac{a^3\, -\, b^3}{a\, -\, b} The answer is suppose to be a^2\, +\, ab\, +\, b^2 I've tried to factor a^3\, -\, b^3 but it still didn't lead up to the answer. What steps are required here? Apply the formula for factoring differences of cubes . That, or do the long polynomial division . :clap:

- Wed Apr 15, 2015 4:56 pm
- Forum: Statistics
- Topic: Normal Deviation junk
- Replies:
**3** - Views:
**227**

80 is two deviations from the mean. How do I find out the percentage when no other info is given? I'm sorry; I'd assumed that your class had covered normal distributions already. To learn about percentages related to deviations, try here or here . After you've studied the two lessons, paying close ...

- Sun Apr 12, 2015 2:14 am
- Forum: Statistics
- Topic: Normal Deviation junk
- Replies:
**3** - Views:
**227**

A normal distribution has a mean of 100 and a standard deviation of 10. Find the probability that a value selected at random is in the given interval: from 80 to 100 How in the world am I suppose to draw one if I don't have the info? There is nothing in the instructions about drawing a picture. Ins...

- Mon Mar 30, 2015 5:23 pm
- Forum: Beginning Algebra
- Topic: Linear independence & linear dependence
- Replies:
**1** - Views:
**337**

Suppose that vectors v1,v2,v3 are linearly independent. (i) Prove that v1-v2, v2-v3 and v3-v1 are linearly dependent. (ii) Prove that v1+v2, v2+v3 and v3+v1 are linearly dependent. I need you guys to help me solve this question.... To learn how to show linear dependence try here . Then set things u...

- Fri Jan 16, 2015 3:18 pm
- Forum: Trigonometry
- Topic: angles of a oblique triange
- Replies:
**4** - Views:
**696**

I think the usual way of saying it would like something like this:

"ABC is a triangle. Opposite the vertices A, B, and C are the sides a, b, and c, respectively. The lengths of the sides are: a = 88, b = 72, and c = 110. Find the measures of the angles at A and at C."

"ABC is a triangle. Opposite the vertices A, B, and C are the sides a, b, and c, respectively. The lengths of the sides are: a = 88, b = 72, and c = 110. Find the measures of the angles at A and at C."

- Fri Jan 16, 2015 3:14 pm
- Forum: Beginning Algebra
- Topic: Domain and Range of a relation
- Replies:
**5** - Views:
**1086**

Then which is the independent variable and which is the dependent variable? The domain and range depend on this information! Thanks!

- Thu Jan 15, 2015 12:27 pm
- Forum: Intermediate Algebra
- Topic: Pondering Base and Exponent, Both NEGATIVE
- Replies:
**3** - Views:
**687**

I wrote up a problem for myself to test the behavior of a negative exponent with a negative base.... y\, =\, \dfrac{(-5)^{-x}}{34} Before I proceed, I will do a mini-proof of the numerator. (-5)^{-x}\, =\, \dfrac{x}{(-5)^1}\, =\, \dfrac{x}{(-5)} Is this math correct?...

- Sat Nov 22, 2014 2:03 pm
- Forum: Statistics
- Topic: I need help to solve this question
- Replies:
**1** - Views:
**876**

The following table represents the absent days of a sample of students in the statistics course Absent days 0 1 2 3 4 Number of students 10 5 8 Y 3 Determine the value of Y if the median of the absent days is 1.5 day. The " median " is the middle value in the list. So write out the list: ...

- Mon Nov 10, 2014 6:29 pm
- Forum: Statistics
- Topic: Expected Value of Probability Density Function
- Replies:
**1** - Views:
**667**

I am trying to find the Expected Value of the following Probability Density Functions (where E is Euler's number) for the x values shown below. For some reason I get very different values from my calculations of the expected value when applying the discrete and continuous method of calculating expe...