- Fri Nov 13, 2015 9:29 pm
- Forum: Trigonometry
- Topic: Finding all the solutions of the equation
- Replies:
**4** - Views:
**57**

Sorry, I honestly have no idea, why would you do that? :confused: I think the poster was trying to point out that your equation is a quadratic type so you can apply the same formulas. Here you can plug into the quadratic formula (at the link in that post) to get simple solve-able trig equations. So...

- Fri Nov 06, 2015 7:28 pm
- Forum: Calculus
- Topic: Integration using algebraic substitution
- Replies:
**4** - Views:
**115**

bazbeatz wrote:Well then i get...

=1/30 (5(x-2)^6 + 12(x-2)^5)+C

which is still different to the answer provided unless i am missing something

What happens when you take the common factor of (x - 2)

(1/30) [ 5(x - 2)

- Fri Nov 06, 2015 2:09 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Equation for a square
- Replies:
**1** - Views:
**82**

But that "astroid" is a curve. A square isn't curved, so the same kind of equation probably won't work. The only thing I could find is stuff like here. Good luck!

- Fri Nov 06, 2015 2:07 am
- Forum: Calculus
- Topic: Integration using algebraic substitution
- Replies:
**4** - Views:
**115**

What do you get if you do the back-subbing to get back to "x" (instead of "u")?

- Thu Nov 05, 2015 12:51 am
- Forum: Uncategorized
- Topic: Tick tock!
- Replies:
**2** - Views:
**75**

In a 12 hours period, starting exactly at 00.00, how often does: 1: the minute hand overlap the hour hand The minute hand doesn't cross over the hour hand from midnight (00:00:01) to 1am because the minute hand is always "ahead" of the hour hand. The minute hand crosses over once an hour ...

- Tue Oct 20, 2015 11:58 pm
- Forum: Intermediate Algebra
- Topic: inverse f(inverse g(x)) = inverse g(inverse f(x))
- Replies:
**2** - Views:
**95**

f(x) = 24x-15 and g(x)=2x-d where d is an unknown value, it is known that inverse f(inverse g(x)) = inverse g(inverse f(x)) I have to first of all find the value of d, and secondly find; inverse f(inverse g(20)) We have been using mathCAD to solve similar but I really want to learn how to solve thi...

- Tue Oct 20, 2015 11:39 pm
- Forum: Discrete Math
- Topic: Prove or disprove: If f:X->Y and g:Y->X are functions such that g o f = I_x and f o g = I_y, then
- Replies:
**1** - Views:
**163**

Pharlap7404 wrote:Prove or give a counterexample:

If f:X->Y and g:Y->X are functions such that g o f = I_{x}and f o g = I_{y}

then f and g are both one-to-one and onto and g = f^{-1}

What is "I

- Sat Oct 10, 2015 7:29 pm
- Forum: Intermediate Algebra
- Topic: using factor method to solve cubic inequality
- Replies:
**2** - Views:
**70**

Please can you help apply the factor method ( reference lesson on this topic) to find solution intervals. I can get the answer using test values but not via the method you illustrate in your lesson on this topic The lesson here ? If yes, then: x^3 - 3x^2 - 9x + 27 < 0 This solves as x^2 (x-3) - 9 (...

- Fri Oct 02, 2015 8:06 pm
- Forum: Trigonometry
- Topic: Help for calculating a point inside a pitched draw
- Replies:
**3** - Views:
**184**

It looks like coordinates have been given for the top (and bottom) corner points. Do you mean the *interior* points on the frame? When you answer, please show your work so far. Thank you!

- Thu Oct 01, 2015 8:42 pm
- Forum: Statistics
- Topic: How to interpolate this.
- Replies:
**3** - Views:
**211**

I have Y vectors = (0, 5, 10, 15, 20) At Condition1, x Vectors = (-0.0056, 5.0000, 10.0057, 15.0057, 20.0000) At Condition2, x vectors = (-0.0028, 5.0028, 10.0085, 15.0085, 20.0028) At Condition3, x vectors = ( 0.0000, 5.0056, 10.0113, 15.0113, 20.0056) There can happen many conditions between cond...