The Purplemath Forums

Hi Lotrnerd,

Minor mistake here:

a + a/2 + (a/2)/2 + 3[(a/2)/2] = 180
a + a/2 + (a/2 * 1/2) + 3((a/2) * (1/2)) = 180
a + a/2 + a/4 + 3a/4 = 180

Here you have to multiply by 4 to clear the fractions:

4a + 2a + a + 3a = 720
10a = 720
a = 72

Maximum:
x = 200 + 5
x = 205 (degrees Fahrenheit)

Minimum:
x = 200 - 5
x = 195 (degrees Fahrenheit)

You can always check your answers using WolframAlpha:

http://goo.gl/lRNOV

This matches MrAlgebra's answer.

How come I can't use the BBCode url tags?
I see that other members can.

It looks like it's working now:

WolframAlpha calculation

Previously, I received an error message which said I that the url tags were turned off.
Maybe a mechanism to keep spammers away?

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