I have to solve: |x^2-3x|-2=0

i have to solve for |x^2-3x|=2 and for |x^2-3x|=-2 right?

for |x^2-3x|=-2 i have

x^2-3x=-2

x^2-3x+2=0

(x-1)(x-2)=0

so x=1,2

but what can i do for |x^2-3x|=2?

- Sun Nov 10, 2013 7:01 pm
- Forum: Intermediate Algebra
- Topic: Solve |x^2-3x|-2=0
- Replies:
**1** - Views:
**3218**

I have to solve: |x^2-3x|-2=0

i have to solve for |x^2-3x|=2 and for |x^2-3x|=-2 right?

for |x^2-3x|=-2 i have

x^2-3x=-2

x^2-3x+2=0

(x-1)(x-2)=0

so x=1,2

but what can i do for |x^2-3x|=2?

i have to solve for |x^2-3x|=2 and for |x^2-3x|=-2 right?

for |x^2-3x|=-2 i have

x^2-3x=-2

x^2-3x+2=0

(x-1)(x-2)=0

so x=1,2

but what can i do for |x^2-3x|=2?