without using a truth table prove the following:

(j--->a) and (s--->h) and (j or s) ---> (a--->j) or (h--->s)

- Mon Oct 21, 2013 3:04 am
- Forum: Discrete Math
- Topic: solve using inference and logic equivalence rules
- Replies:
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**1490**

without using a truth table prove the following:

(j--->a) and (s--->h) and (j or s) ---> (a--->j) or (h--->s)

(j--->a) and (s--->h) and (j or s) ---> (a--->j) or (h--->s)