- Fri Oct 04, 2013 3:02 am
- Forum: Beginning Algebra
- Topic: help solving rational equation
- Replies:
**4** - Views:
**3333**

Thanks guys. you made my day. be back soon!

- Thu Oct 03, 2013 8:28 pm
- Forum: Beginning Algebra
- Topic: help solving rational equation
- Replies:
**4** - Views:
**3333**

at what point do i solve the quadratic. after i multiply by common denominators I got: (x)(x) - (x+1)(x+3) = (x-1)(-3) ...

this is how i set up the cancellations: (x)(x+1)(x-1)*(x/(x-1)(x+1) - (x)(x+1)(x-1)*(x+3)/(x(x-1)) = (x)(x+1)(x-1)* -3/(x(x+1))

this is how i set up the cancellations: (x)(x+1)(x-1)*(x/(x-1)(x+1) - (x)(x+1)(x-1)*(x+3)/(x(x-1)) = (x)(x+1)(x-1)* -3/(x(x+1))

- Thu Oct 03, 2013 3:31 pm
- Forum: Beginning Algebra
- Topic: help solving rational equation
- Replies:
**4** - Views:
**3333**

This is actually in the Linear Equations section of my book. I've looked everywhere for a similar problem. please help me break it down.

x/(x^2-1) - (x+3)/(x^2-x) = -3/(x^2+x)

x/(x^2-1) - (x+3)/(x^2-x) = -3/(x^2+x)