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Functions eg. f(x+2), f(2x)+2,  TOPIC_SOLVED

If f(x) = 4x^2 + 3x - 2 write down the following in their simplest form. a) f(x) +4 = 4x^2 + 3x - 2 +4 = 4x^2 +3x + 2 (this one I think i understand.) b) f(2x) + 2 = i dont know how to do this one. = 2( 4x^2 + 3x - 2) +2? c) f(x+2) - 20 = ? d) f (x-1)+1 + ? e) f(x/2) = 4x^2 + 3x - 2/2 ?? f) f (3x+2)...
by Nats
on Mon Aug 19, 2013 11:33 am
 
Forum: Intermediate Algebra
Topic: Functions eg. f(x+2), f(2x)+2,
Replies: 2
Views: 1372

Re: Functions eg. f(x+2), f(2x)+2,  TOPIC_SOLVED

b) 4(4x^2)+3(2x)+2-2 = 16x^2+6x I'm so grateful for your help. I didn't think I'd get a reply so soon considering none of the problems on the first page were answered. Then you not only helped me but you went and answered like the whole page of other learners problems as well. Thank you so much, you...
by Nats
on Tue Aug 20, 2013 8:30 am
 
Forum: Intermediate Algebra
Topic: Functions eg. f(x+2), f(2x)+2,
Replies: 2
Views: 1372

4x^3 - 10x^2 + 2= 0 What do I do with the cube?  TOPIC_SOLVED

How do you solve these types of quadratics with cubes and squares? please explain and give a few more examples
I did read Factoring quadratics: the weird case, but I didn't find any example that matches the one I'm currently struggling with.


Thank you. Your help is greatly appreciated.
by Nats
on Thu Aug 22, 2013 11:06 am
 
Forum: Intermediate Algebra
Topic: 4x^3 - 10x^2 + 2= 0 What do I do with the cube?
Replies: 4
Views: 1278

Re: 4x^3 - 10x^2 + 2= 0 What do I do with the cube?  TOPIC_SOLVED

thanks for your reply.

I divided through by two
2x^3 -5x^2 -1 = 0

Im still stuck.
how would i solve this without a calculator?

How do you graph something like this? Isn't I need something like y = mx + b

The link returned an error.
by Nats
on Thu Aug 22, 2013 1:13 pm
 
Forum: Intermediate Algebra
Topic: 4x^3 - 10x^2 + 2= 0 What do I do with the cube?
Replies: 4
Views: 1278

given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)  TOPIC_SOLVED

f(x) = x^2 - 4x + 3 and g(x)= 2x - 1

solve f(x)=g(x)

x^2 - 4x + 3 = 2x - 1
-2x -2x
x^2 - 6x = -4
x^2 - x = -2/3

and now I'm stuck?

How do i get rid of x^2 - x?
by Nats
on Thu Aug 22, 2013 1:20 pm
 
Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 12886

Re: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g  TOPIC_SOLVED

@jg.allinsymbols, thanks again for your helpful reply.

starting from x^2 - 6x = -4.
x^2 - 6x + 4 = 0

using the quadratic formula:
-(-6) +- [(sqrt)-6^2 - 4(1)(4)]/2(1)
6+-(sqrt 20)/2
6+-(sqrt 4x5)/2
6+-2(sqrt 5)/2 and i cancel out the twos
6+-2.24

x = 8.25 or x= 3.76

is this correct?
by Nats
on Fri Aug 23, 2013 11:09 am
 
Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 12886

Re: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g  TOPIC_SOLVED

@maggie, thank you for your reply as well.
by Nats
on Fri Aug 23, 2013 11:11 am
 
Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 12886

Linear Programming  TOPIC_SOLVED

A builder is planning to build houses on a 9000m^2 plot of land. Some of the houses will be small. The others will be large. The number of small houses is represented by S. The number of large houses are represented by L. The authorities insist that there must be more small houses than large houses,...
by Nats
on Fri Aug 23, 2013 2:41 pm
 
Forum: Intermediate Algebra
Topic: Linear Programming
Replies: 4
Views: 1161

Re: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g  TOPIC_SOLVED

But this is totally not what the Quadratic Formula gives, so I think you mean like this: \frac{-(-6)\, \pm\, \sqrt{(-6)^2\, -\, 4(1)(4)}}{2(1)} \frac{6\, \pm\, \sqrt{36\, -\, 16}}{2} \frac{6\, \pm\, \sqrt{20}}{2} \frac{6\, \pm\, \sqrt{4\times 5}}{2} yes. from...
by Nats
on Mon Aug 26, 2013 10:45 am
 
Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 12886

Re: Linear Programming  TOPIC_SOLVED

I'm sorry, but I do not follow your reasoning. It appears that you have attempted to include at least three different conditions in one equation or inequality. It would likely be more helpful to work in an orderly fashion, clearly stating one's reasoning and processing the information step-by-step....
by Nats
on Mon Aug 26, 2013 10:58 am
 
Forum: Intermediate Algebra
Topic: Linear Programming
Replies: 4
Views: 1161
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