- Mon Aug 26, 2013 6:20 pm
- Forum: Intermediate Algebra
- Topic: Finding gradient of a tangent
- Replies:
**4** - Views:
**4699**

what method do they teach you for finding the gradient at a point on a curved line? i only know calc so you need to say what other thing you're supposed to use. thnx In my textbook it states: to calculate the gradient of a curve at a specific point, the following steps need to be taken: *draw a tang...

- Mon Aug 26, 2013 6:00 pm
- Forum: Intermediate Algebra
- Topic: Linear Programming
- Replies:
**4** - Views:
**2338**

Firstly, thank you very much @buddy. OK, Im getting super, super frustrated, and Im sure you think Im super dumb, but I'll just keep trying till I get it right and hopefully you'll keep helping me till I do. 2nd attempt @nona's reasoning and processing step-by-step with @buddy's replies. a) For what...

- Mon Aug 26, 2013 4:20 pm
- Forum: Intermediate Algebra
- Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
- Replies:
**9** - Views:
**59046**

I cancelled it out with the 2 I got from the sqrt of 4.

- Mon Aug 26, 2013 11:56 am
- Forum: Intermediate Algebra
- Topic: k= 3x^2 - x^3
- Replies:
**3** - Views:
**1556**

The equation k= 3x^2 - x^3 is satisfied by one value for x between -2 and 4. what can be said about the value of k? think of this like 2 functions: Y1 = 3x^2 - x^3 & Y2 = k. look at the graph of Y1 and think abt where you'd only get ONE number for x going with a number for y = Y2 = k. (but you prob...

- Mon Aug 26, 2013 11:48 am
- Forum: Intermediate Algebra
- Topic: Finding gradient of a tangent
- Replies:
**4** - Views:
**4699**

Im taking Cambridge IGCSE Mathematics (0581)

This is a question for my assignment. the graph is already drawn.

This is a question for my assignment. the graph is already drawn.

- Mon Aug 26, 2013 11:09 am
- Forum: Intermediate Algebra
- Topic: k= 3x^2 - x^3
- Replies:
**3** - Views:
**1556**

The equation k= 3x^2 - x^3 is satisfied by one value for x between -2 and 4. what can be said about the value of k?

- Mon Aug 26, 2013 11:05 am
- Forum: Intermediate Algebra
- Topic: Finding gradient of a tangent
- Replies:
**4** - Views:
**4699**

A curve with the equation: y= 3x^2 - x^3

tangent drawn at point (3,0)

how to find the gradient?

tangent drawn at point (3,0)

how to find the gradient?

- Mon Aug 26, 2013 11:01 am
- Forum: Intermediate Algebra
- Topic: 4x^3 - 10x^2 + 2= 0 What do I do with the cube?
- Replies:
**4** - Views:
**2673**

- Mon Aug 26, 2013 10:58 am
- Forum: Intermediate Algebra
- Topic: Linear Programming
- Replies:
**4** - Views:
**2338**

I'm sorry, but I do not follow your reasoning. It appears that you have attempted to include at least three different conditions in one equation or inequality. It would likely be more helpful to work in an orderly fashion, clearly stating one's reasoning and processing the information step-by-step....

- Mon Aug 26, 2013 10:45 am
- Forum: Intermediate Algebra
- Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
- Replies:
**9** - Views:
**59046**

But this is totally not what the Quadratic Formula gives, so I think you mean like this: \frac{-(-6)\, \pm\, \sqrt{(-6)^2\, -\, 4(1)(4)}}{2(1)} \frac{6\, \pm\, \sqrt{36\, -\, 16}}{2} \frac{6\, \pm\, \sqrt{20}}{2} \frac{6\, \pm\, \sqrt{4\times 5}}{2} yes. from here \frac{6\, \pm\, \sqrt{4\times 5}}{...