Search found 18 matches

Functions eg. f(x+2), f(2x)+2,

If f(x) = 4x^2 + 3x - 2 write down the following in their simplest form. a) f(x) +4 = 4x^2 + 3x - 2 +4 = 4x^2 +3x + 2 (this one I think i understand.) b) f(2x) + 2 = i dont know how to do this one. = 2( 4x^2 + 3x - 2) +2? c) f(x+2) - 20 = ? d) f (x-1)+1 + ? e) f(x/2) = 4x^2 + 3x - 2/2 ?? f) f (3x+2)...
on Mon Aug 19, 2013 11:33 am

Forum: Intermediate Algebra
Topic: Functions eg. f(x+2), f(2x)+2,
Replies: 2
Views: 1176

Re: Functions eg. f(x+2), f(2x)+2,

b) 4(4x^2)+3(2x)+2-2 = 16x^2+6x I'm so grateful for your help. I didn't think I'd get a reply so soon considering none of the problems on the first page were answered. Then you not only helped me but you went and answered like the whole page of other learners problems as well. Thank you so much, you...
on Tue Aug 20, 2013 8:30 am

Forum: Intermediate Algebra
Topic: Functions eg. f(x+2), f(2x)+2,
Replies: 2
Views: 1176

4x^3 - 10x^2 + 2= 0 What do I do with the cube?

How do you solve these types of quadratics with cubes and squares? please explain and give a few more examples
I did read Factoring quadratics: the weird case, but I didn't find any example that matches the one I'm currently struggling with.

Thank you. Your help is greatly appreciated.
on Thu Aug 22, 2013 11:06 am

Forum: Intermediate Algebra
Topic: 4x^3 - 10x^2 + 2= 0 What do I do with the cube?
Replies: 4
Views: 1163

Re: 4x^3 - 10x^2 + 2= 0 What do I do with the cube?

I divided through by two
2x^3 -5x^2 -1 = 0

Im still stuck.
how would i solve this without a calculator?

How do you graph something like this? Isn't I need something like y = mx + b

on Thu Aug 22, 2013 1:13 pm

Forum: Intermediate Algebra
Topic: 4x^3 - 10x^2 + 2= 0 What do I do with the cube?
Replies: 4
Views: 1163

given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)

f(x) = x^2 - 4x + 3 and g(x)= 2x - 1

solve f(x)=g(x)

x^2 - 4x + 3 = 2x - 1
-2x -2x
x^2 - 6x = -4
x^2 - x = -2/3

and now I'm stuck?

How do i get rid of x^2 - x?
on Thu Aug 22, 2013 1:20 pm

Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 9552

Re: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g

starting from x^2 - 6x = -4.
x^2 - 6x + 4 = 0

-(-6) +- [(sqrt)-6^2 - 4(1)(4)]/2(1)
6+-(sqrt 20)/2
6+-(sqrt 4x5)/2
6+-2(sqrt 5)/2 and i cancel out the twos
6+-2.24

x = 8.25 or x= 3.76

is this correct?
on Fri Aug 23, 2013 11:09 am

Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 9552

Re: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g

on Fri Aug 23, 2013 11:11 am

Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 9552

Linear Programming

A builder is planning to build houses on a 9000m^2 plot of land. Some of the houses will be small. The others will be large. The number of small houses is represented by S. The number of large houses are represented by L. The authorities insist that there must be more small houses than large houses,...
on Fri Aug 23, 2013 2:41 pm

Forum: Intermediate Algebra
Topic: Linear Programming
Replies: 4
Views: 1030

Re: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g

But this is totally not what the Quadratic Formula gives, so I think you mean like this: \frac{-(-6)\, \pm\, \sqrt{(-6)^2\, -\, 4(1)(4)}}{2(1)} \frac{6\, \pm\, \sqrt{36\, -\, 16}}{2} \frac{6\, \pm\, \sqrt{20}}{2} \frac{6\, \pm\, \sqrt{4\times 5}}{2} yes. from...
on Mon Aug 26, 2013 10:45 am

Forum: Intermediate Algebra
Topic: given f(x) = x^2 - 4x + 3 and g(x)= 2x - 1, solve f(x)=g(x)
Replies: 9
Views: 9552

Re: Linear Programming

I'm sorry, but I do not follow your reasoning. It appears that you have attempted to include at least three different conditions in one equation or inequality. It would likely be more helpful to work in an orderly fashion, clearly stating one's reasoning and processing the information step-by-step....
on Mon Aug 26, 2013 10:58 am

Forum: Intermediate Algebra
Topic: Linear Programming
Replies: 4
Views: 1030
Next