Search found 1 match

Return to advanced search

Re: Prove that a^2|b and b^3|c then a^4b^5|c^3.  TOPIC_SOLVED

a^2|b so b = a * a * j
b^3|c so c = b * b * b * k
c^3 = b * b * b * k * b * b * b * k * b * b * b * k = b * b * b * k * b * b * b * k * b * a * a * j * a * a * j * k = a^4 * b^7 * j^2 * k^3
a^4 * b^7 * j^2 * k^3/a^4b^5 = b^2 * j^2 * k^3, which is an integer, so a^4b^5 | c^3
by rsood
on Wed Aug 07, 2013 12:14 am
 
Forum: Discrete Math
Topic: Prove that a^2|b and b^3|c then a^4b^5|c^3.
Replies: 1
Views: 1278

Return to advanced search