2(2

^{n-1}) = 2

^{n}but I don't see how this is.

It seems to me that 2(2

^{n-1}) = 4

^{n-1}

What is the rule at work here?

- Wed Apr 03, 2013 3:00 am
- Forum: Advanced Algebra ("pre-calculus")
- Topic: Product involving a difference as an exponent
- Replies:
**1** - Views:
**1922**

I'm learning discrete math, but having a problem with an algebraic simplification, so I think I'm posting this in the right place.

2(2^{n-1}) = 2^{n} but I don't see how this is.

It seems to me that 2(2^{n-1}) = 4^{n-1}

What is the rule at work here?

2(2

It seems to me that 2(2

What is the rule at work here?